Volume of Revolution for Polynomial Bowl

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Homework Help Overview

The discussion revolves around creating a volume of revolution for a polynomial bowl by rotating polynomial equations around the y-axis. The original poster presents three polynomial equations and seeks guidance on how to handle the intersection of two functions that form a minimum at the bottom of the bowl.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the potential methods for calculating the volume, including the disc method and shell method. There is a suggestion to simplify the problem with alternative equations to facilitate integration.

Discussion Status

Participants are exploring different approaches to the problem, with some suggesting alternative equations for easier integration. There is a recognition of the need for limits of integration, and some participants express appreciation for the guidance provided by others.

Contextual Notes

There is mention of specific requirements for using certain methods (disc/washer vs. shell) and the need for exact values before integration. The original poster's equations and the constraints of the problem are under discussion.

reybob
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Homework Statement


The question asked is to make a bowl out of polynomial equations rotated around the y axis. The bottom of the bowl has to have a maximum at the center and a minimum at some distance from the center.

The equations I want to use are x^2+10, 1.3x^2 and -.7x^2 + 4.

The problem I face is what to do about the bottom of the bowl, since it is comprised of 2 functions meeting to form a minimum. Should I treat those two as its own volume of revolution, find the volume and then subtract the interior (top of bowl) from that total?

Homework Equations



Disc method: pi*integ: r(y)^2 dy


The Attempt at a Solution



pi*Integ: ((y-10)^1/2)^2 - [pi*Integ: ((y/1.3)^1/2)^2 - ((y-4/.7)^1/2)^2]

Is my attempt correct? The volume I am trying to find is bounded by x=0 (the y axis) and the 3 other equations

 

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Does this exercise allow us our own equations?
Why not simplify it with?
"y= x^2/2+30,y=1/8 x^4 -x^2 +5"
This allows us one integral with shell method.If that's not allowed, we'll need at least two separate integrations.
Are you required disc/ washer method? I think this exercise is easier with shell method on your equations. Then it can be done with only two integrals.

Disc/ washer method will require 3 separate integrals.
all numbers are approximate, but must be found exactly or more precisely before integrating.
The limits of integration
y:2.5->4 washer method
y:4->10 disk method
y:10->45 washer method
For washer method it's always pi[(outer radius)^2 - (inner radius)^2]
Disk method is a simplification of the same formula, with inner radius =0.Either way, we definitely need limits of integration.
Without limits of integration, I can't tell how close you are to an effective method.
 
Last edited:
We can use our own, I going to take your advice and use those equations! I couldn't find a curve that looked like that, this is much easier to work with! Thank you so much, this makes my life much easier!
 
I knew some 4th degree function had the desired behavior. I just played around with wolframAlpha.com until I had the right graph.

An even function is symmetric on both sides of the y axis.
So only x^2 & x^4, & constant terms.

I first tried x^4 +x^2 with various coefficients but that did not give any of the needed humps. Then I realized x^4 term & x^2 needed to go the opposite direction. From there I just fine tuned the coefficients until it looked nice.

WolframAlpha.com is the best thing since sliced bread. Nearly instant graphing, less strict syntax to learn.

Have fun in your learning.
 

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