Volume/Volume %, manipulating units

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To determine the volume/volume percentage of acetic acid in vinegar, the concentration of acetic acid in mol/L needs to be converted into grams per 100 mL, using the density of acetic acid and vinegar. The user has concentrations of acetic acid in both the vinegar and a diluted sample, which complicates identifying the total volumes of A (acetic acid) and A+B (total solution). It is crucial to clarify that A represents the volume of acetic acid in the original vinegar, while A+B includes the volume of acetic acid in the diluted sample. The conversion from mol/L to grams/L is essential for calculating the final volume/volume percentage. Accurate calculations will provide the desired percentage of acetic acid in the vinegar solution.
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I am trying to find % acetic acid by volume in vinegar.

I have 8*10-4 mol/L of acetic acid in vinegar and 8*10-5 of acetic acid in the dilute sample of vinegar and water.

I know that the volume/volume % is equal to the amounts of A divided by the total amounts of A and B. BUT that they also should be in mL, considering the density (the assumed density) of water, vinegar and acetic acid is 1.00g/mL.

So I'm having trouble with finding out how to convert the mol/L into just mL. Also having trouble figuring out what A and A+B are. I am assuming A is the volume of acetic acid in vinegar and A+B is the volume of acetic acid in the dilute sample?

Thanks
 
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mol/L can be converted into grams/L which can be converted into grams/100mL.
 
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