Wall thickness vs frequency.... sound isolation

Click For Summary
SUMMARY

The discussion centers on the relationship between wall thickness, frequency, and sound isolation, emphasizing that acoustic impedance alone is insufficient for predicting sound transmission. It highlights that while aluminum has a significantly higher acoustic impedance than air, factors such as wall thickness and frequency must be considered to accurately assess sound reflection and transmission. Thicker walls generally reflect more sound, but low frequencies penetrate walls more effectively than high frequencies. The user seeks a method to calculate sound transmission through walls based on these variables.

PREREQUISITES
  • Understanding of acoustic impedance and its significance in sound transmission.
  • Knowledge of frequency and its impact on sound behavior.
  • Familiarity with wall construction materials and their acoustic properties.
  • Basic principles of sound reflection and transmission.
NEXT STEPS
  • Research "sound transmission loss of building materials" for practical examples and calculations.
  • Learn about "acoustic modeling software" to simulate sound transmission scenarios.
  • Explore "ISO 140-3 standards" for measuring sound insulation in buildings.
  • Investigate "mass law" in acoustics to understand the relationship between mass, frequency, and sound isolation.
USEFUL FOR

Acoustic engineers, soundproofing specialists, architects, and anyone involved in designing spaces for optimal sound isolation will benefit from this discussion.

Trontron
Messages
1
Reaction score
0
When sound hits a wall,part of it gets reflected and part of it gets transmitted due to acoustic impedance difference between solid and air.

My problem,and point of this question is that having material or gas impedance number is completely useless unless we know the frequency and wall thickness.Let me give you an example.

Acoustic impedance of aluminum is 35000 times bigger than impedance of air,if all we looked at was impedance difference,we would assume every time sound in air hits anything made of aluminum,then it will reflect back 99.9965% sound energy,and 0.0035% gets inside.

If you tried to isolate subwoofer playing 40 Hz tone with aluminum foil,you will see it doesn't work like that,becose sound reflection and transmission depend on two aditional factors,frequency and wall thickness.

Thicker walls are more reflective than thin walls made of same material with same acoustic impedance.Low fequencies reflect less and more easily penetrate walls than higher frequencies.That means effective impedance depends on frequency and thickness,so if the wall is thin and frequency low,the effective impedance difference is much lower than intrinsic impedance of the two materials or gases.

How can I calculate how much sound will get transmitted through wall at certain frequency and certain wall thickness? I would like to be able to calculate graph where one axis is frequency,and other axis sound energy transmitted to other side with wall of certain material and thickness.
 
Engineering news on Phys.org

Similar threads

  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 31 ·
2
Replies
31
Views
5K
  • · Replies 9 ·
Replies
9
Views
6K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K