How Much Force to Hold a Fire Hose Delivering Water at High Speed?

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SUMMARY

The discussion focuses on calculating the force required to hold a fire hose delivering water at high speed, specifically a 7.5 cm diameter hose with a flow rate of 470 L/min through a 0.80 cm diameter nozzle. Using the continuity equation and Bernoulli's equation, the velocities were determined to be 38.97 m/s in the nozzle and 1.77 m/s in the hose. The pressure in the hose was calculated to be 857,830.4646 Pa, leading to a force of 3,789.8 N. However, the initial calculations were questioned, suggesting an alternative approach using impulse to determine the force exerted by the water.

PREREQUISITES
  • Understanding of fluid dynamics principles, specifically the continuity equation and Bernoulli's equation.
  • Knowledge of pressure calculations and force equations in physics.
  • Familiarity with units of measurement in fluid dynamics, such as liters per minute and pascals.
  • Basic understanding of impulse and momentum concepts in physics.
NEXT STEPS
  • Study the application of the continuity equation in fluid flow scenarios.
  • Learn about Bernoulli's equation and its implications in real-world fluid dynamics.
  • Explore the concept of impulse and how it relates to forces in fluid systems.
  • Investigate practical examples of force calculations in firefighting equipment and other high-pressure fluid systems.
USEFUL FOR

This discussion is beneficial for physics students, engineers in fluid dynamics, and professionals in firefighting equipment design, particularly those interested in the mechanics of high-speed water delivery systems.

aishjay
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1. A fire hose exerts a force on the person holding it. This is because the water accelerates as it goes from the hose through the nozzle. How much force is required to hold a 7.5 cm diameter hose delivering 470 L/min through a 0.80 cm diameter nozzle?

Homework Equations



I think we need to use the continuity eqn: A1V1 = A2V2 = Q
and the Bernoulli eqn: P + (rho)gh + 1/2 (rho)v^2 = constant

The Attempt at a Solution



Using the continuity equation, I found the velocities in the nozzle and in the hose
V1 (in nozzle) = 38.97 m/s
V2 (in hose) = 1.77 m/s

Then I used the bernoulli equation to solve for the pressure in the hose.
P1 = P2 + 1/2 (rho)[(v2)^2-(v1)^2]
with P2 = 1.0*10^5 Pa
P1 = 857830.4646 Pa

Then I said P = F/A
F = PA = 857830.4646 Pa(Area of hose)
F = 3789.8 N

But this is the wrong answer - I wonder if my logic itself is faulty?
 
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Have you tried using the change of impulse of a small mass dm of water instead? This change of impulse should be equal to the force the brave fire fighter is using to hold the nozzle.
 

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