Water Temperature mixing together

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Homework Help Overview

The problem involves mixing two quantities of water at different temperatures: 1 kg at 100°C and 10 kg at 0°C. The goal is to determine the equilibrium temperature after mixing.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the heat transfer formula and the concept of equilibrium temperature. Some express uncertainty about the correct formula to use, while others suggest using a heat balance approach to solve for the final temperature.

Discussion Status

The discussion is ongoing, with participants exploring different methods to approach the problem. Some have provided calculations and reasoning, while others are questioning the assumptions and the implications of their findings.

Contextual Notes

There is a mention of potential complications if ice were involved, indicating that latent heat considerations might alter the scenario. Participants also note the importance of understanding the weighted average concept in this context.

strawberry7
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Homework Statement


When 1 kg of water at 100 C is mixed with 10 Kg of water at 0C, the equilibrium temperature will be:

a) exactly 0 C
b) Exactly 50 C
C) Exactly 100 C
d) slightly above 0 C

I think that the answer is D) sligtly above 0 C, but i don't know why. I'm not sure what formula to use, and I've been lookking all over the web and my textbook.
 
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When you add 1 kg of water in the liquid phase at 100 C, you can find the heat given out by it when its brought down to T c. That is equal to the heat gained by the 10 kg of water at 0c to come to Tc. Solve for T (final temperature).
 
so am i sopposed to use the Q= mc (Change in temperature) formula

so like 1 * 4186 * 100
Q = 418600And then 418600 = 10 *4186 *?
= 41860 * t
418600/41860 = t
t = 10

So it's slightly over 0 C ?
 
yea, intuitively you can see this is a weighted average kind of problem,
10 parts at 0, 1 part at 100, so ave for 11=9.09 degrees. Now if the water was ice, different animal as latent heats need to be included.
 

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