Wave Velocity Calculation: y = 0.02 sin[ pi(30x - 400t)] in SI units

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SUMMARY

The wave described by the equation y = 0.02 sin[ pi(30x - 400t)] has a velocity of 40/3 m/s. The correct calculation involves identifying the wave's angular frequency and wave number, leading to the formula v = ω/k, where ω = 400π and k = 30π. The misunderstanding arose from confusing the maximum velocity at a point with the wave's propagation velocity. The final derived velocity is confirmed as 40/3 m/s, aligning with the correct answer choice.

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Homework Statement


For a wave described by y = 0.02 sin[ pi(30x - 400t)] (SI units), the velocity of the wave (in m/s) is

a) 3/40 b) 40/3 c) (60pi)/400 d)400/(60pi) e) 400

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The Attempt at a Solution


I found the derivative of the function as v= -25.132 cos[pi(30x-400t)] so I assumed the velocity is 25.132 m/s which is none of the options and the correct answer is 40/3.
 
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they wanted the velocity of the disturbance along the string, not the maximum velocity for one point on the string.
the velocity is hiding in the trig function's argument (kx-ωt) ≈ k(x-vt)
 
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That makes sense! So right now the kx-ωt is (30pi)x-(400pi)t, where k= 30pi. So factoring out 30pi we get v=(400pi)/(30pi) which is 40/3. Thank you!
 

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