Wavelength limits of the Lyman and Paschen series of Hydrogen

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SUMMARY

The discussion focuses on calculating the wavelength limits of the Lyman and Paschen series of hydrogen using the Bohr theory. The Lyman series limit is determined with n0=1, resulting in a wavelength of 91.13 nm, while the Paschen series limit, with n0=3, yields a wavelength of 820.1 nm. The key equation used is λ = λlimit(n2)/(n2-n0), and the limiting values are found by taking the limit as n approaches infinity.

PREREQUISITES
  • Understanding of Bohr's model of the hydrogen atom
  • Familiarity with quantum numbers (n and n0)
  • Knowledge of wavelength calculations in atomic physics
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the derivation of the Bohr model for hydrogen
  • Learn about the significance of quantum numbers in atomic transitions
  • Explore the relationship between energy levels and emitted photon wavelengths
  • Investigate other series in hydrogen, such as the Balmer series
USEFUL FOR

Students of physics, particularly those studying atomic structure and spectral lines, as well as educators seeking to explain the Lyman and Paschen series in hydrogen.

Jadehaan
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Homework Statement



Use the Bohr theory to find the series wavelength limits of the Lyman and Paschen series of hydrogen.

Homework Equations



\lambda=\lambdalimit(n2)/(n2-n02)

Lyman: n0=1
Paschen: n0=3

The Attempt at a Solution



The solutions are 91.13 nm (Lyman) and 820.1 nm (Paschen) but I do not know the process of finding them.

Thanks for any help.
 
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There's another equation relating the wavelength of an emitted photon to the quantum numbers n and n_0...use that equation and take the limit as n\to\infty (why does this provide the limiting value of \lambda?:wink: )
 
Followed your hint; got the answer. Much appreciation.

Thanks again,
Jim
 

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