Weight distribution on a surface

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quick question...
I would like a simplified answer if possible to a simple :) question...

scenario: 80" TV on stand. TV weights - 70 pounds.
In my trivial understanding - 70 pounds will be evenly distributed on each of 4 legs of wooden stand.

TV is centered on the wooden stand. The distance between TV's own plastic stand is 130cm.
The distance between wooden stand legs is180cm (large) and 40cm deep.

My logic saying that 70 pounds will be distributed evenly on each leg. Is it correct thinking, without complex calculation :).

Thank you.
And sorry if the question seems stupid :).
 
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I'm not sure about all of your measurements. The width of an 80" TV screen is about 177cm. But overall, as long as the TV and stand look symmetric from the front, the load will be distributed approximately equally left-to-right (35+35).
Back to front is another issue. Not only will you not hit 50/50 on the first try, but anything pushing or pulling on the TV set at screen level will have a lot of leverage. So, front-to-rear, anything from (0 + 70) to (70 + 0) would be possible.

I don't know why you ask, but if toddlers are nearby, suggest you invest in anti TV tip straps.
 
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wow what a mystery :). Thank you very much for the prompt answer.
At least I know that there is nothing straightforward.
 

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