Weight of block and static friction

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SUMMARY

The weight of the block is 84.0 N, and the coefficient of static friction between the block and the vertical wall is 0.520. To prevent the block from sliding down, the minimum force required is equal to the weight, which is 84.0 N, as the static friction must counteract this weight. To initiate upward movement, the applied force must exceed both the weight and the static frictional force, calculated as the product of the normal force and the coefficient of friction.

PREREQUISITES
  • Understanding of static friction and its coefficient
  • Knowledge of Newton's laws of motion
  • Familiarity with normal force concepts
  • Basic algebra for solving force equations
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  • Study the calculation of normal force in static friction scenarios
  • Learn about the dynamics of forces in vertical motion
  • Explore the implications of varying coefficients of friction
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Homework Statement



The weight of the block in the drawing is 84.0 N. The coefficient of static friction between the block and the vertical wall is 0.520.


(a) What minimum force is required to prevent the block from sliding down the wall? in Newtons

(b) What minimum force is required to start the block moving up the wall? (Hint: The static frictional force is now directed down the wall.)
in Newtons

Homework Equations





The Attempt at a Solution



having problems figuring this out, is there a formula for the force sliding down the wall.
also, wouldn't the minimum be the .520 just the static force?

thanks.
 
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For a static situation, the friction (using static coefficient) must equal the weight.

Friction is given by the product of normal force and coefficient of friction [itex]\mu[/itex].


To get the block moving vertically, the applied force must exceed the weight AND friction.


Friction acts in either (both) directions.
 

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