Weightlessness in a common swing

AI Thread Summary
In a swing, the sensation of weightlessness occurs at the highest point (180 degrees) due to the absence of normal force, as the centripetal acceleration needed to maintain the swing's circular path is zero. Before reaching this point, particularly around 90 degrees, the normal force decreases but does not become zero, leading to a feeling of reduced weight. The discussion highlights that while swinging, a centripetal force acts on the rider, independent of gravity. Additionally, swings with bars allow for higher angles, where weightlessness can be experienced between 90 degrees and the peak. Overall, the dynamics of swinging involve a complex interplay of gravitational and centripetal forces affecting the rider's sensation of weight.
skazis
Messages
8
Reaction score
0
Hi,

Our sensation of weight is given by gravity together with normal forces. It is said that in a swing you'll feel weightless at the top of the ride (180 degrees), because there is no seat that gives you normal force. But from my experience there is something strange even before 180 degrees, when swing stops and goes other way around, just like a free fall. It might be just because after 90 degrees there is no force projection on the seat as well? And this "180 degree fact" is slightly wrong?

Skazis
 
Physics news on Phys.org
Interesting. I must admit I have been to numerous parks with my kids...used the swings and thought about what's going on as well as watch them playing on them.
 
When you swing, you will feel a centripetal force pressing you against the seat (more correctly, pressing the seat against you) but that has nothing to do with gravity- you would feel it even if you were "swinging" in a weightless environment. Of course, in that case your swing would just keep going in a circle.
 
You feel a normal force, because of the centripetal acceleration needed to make you follow a circular arc, and because of the radial component of gravity.

When the swing is a its highest point, there is no centripetal acceleration and there's only the force of gravity.

If the swing makes an angle A with the vertical, the force of gravity mg on you will have a component mg sin (A) which will accelerate the swing tangentially, but will not be felt by someone on the swing. There is also a component mg cos(A), in a radial direction to the outside which is compensated by a normal force in the opposite direction.

The normal force that you feel on the swing (mg cos(A)) becomes 0 when the swing is at 90 degrees. If this is the highest point, you'll be weightless at this point.

On a swing with ropes or chains, you can't go higher than that, unless you go so fast, that the centripetal acceleration at the top of the swing is equal to the acceleration of gravity, and you are then weightless at 180 degrees. This is hardly swinging, because you'd turn circles.

If you make swing with bars, it's possible to swing higher than 90 degrees.(if you can hold on). You would actually become weightless somewhere between 90 degrees and the highest point. (at 90 degrees, there's an inward normal force needed, at the highest point, there's an outward force needed, so you won't fall off head first)
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Hello everyone, Consider the problem in which a car is told to travel at 30 km/h for L kilometers and then at 60 km/h for another L kilometers. Next, you are asked to determine the average speed. My question is: although we know that the average speed in this case is the harmonic mean of the two speeds, is it also possible to state that the average speed over this 2L-kilometer stretch can be obtained as a weighted average of the two speeds? Best regards, DaTario
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Back
Top