Weird words. Someone please clarify.

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SUMMARY

The discussion clarifies the concept of average velocity, specifically how it relates to displacement. Average velocity is defined as the change in position over time, calculated by subtracting the initial position (point A) from the final position (point B). In the example provided, moving from point A at x=5 to point B at x=12 results in a displacement of 7 meters. The average velocity is then determined by dividing this displacement by the time taken, yielding a velocity of 2.5 m/s.

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The average velocity v of an object moving through a displacement during a time interval.

I understand what average velocity is.

My question is what does it mean when an object moves THROUGH a displacement.

I think I've seen this using angles as well.
 
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Noxide said:
The average velocity v of an object moving through a displacement during a time interval.

I understand what average velocity is.

My question is what does it mean when an object moves THROUGH a displacement.

I think I've seen this using angles as well.

It just means that the object moves from point a to point b. The displacement is measured by subtracting point b from point a. When you're working things out theoretically, you have to chose an origin (the place that you want to call x=0).

So if you call point a, five meters from x, and your scale is based on meters, then point as is where x=5. And let's say point b is x=12

Then to move through this displacement, you'd move from x=5 to x=12
the displacement is 12-5 = 7. You've moved 7 meters (i.e. you've displaced the point 7 meters).

Sometimes, you're equation doesn't require knowing the origin or the point a and b, it just requires knowing the displacement. Such is velocity. It's the displacement in position over the displacement in time, so going back to our example, if you've moved 7 meters in 2 seconds, then you're velocity would be:

7m/2s = 2.5 m/s
 

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