- #1

kamehamehaaa

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## Homework Statement

On attachment. Part B only. I got C.

## Homework Equations

mass of proton is 1.673*10^-27

q0 = 1.60*10^-19

## The Attempt at a Solution

For part B I thought I could divide the intial speed by 2 and plug it back into the energy conservation equation:

.5mv^2 + q0V1 = .5mv^2 + q0V2 and solve for (V1 - V2) which would be the potential difference but it doesn't seem to work.