# What amount of amperage do i need for electrolysis of water?

1. Nov 16, 2016

### Ali Durrani

ok i want to make 1g/sec of hydrogen out of an unlimited supply of water, i know the electrolysis wont start below 1.48 volts, let suppose i am supplying 2 volts of DC current, i need to find out the total wattage for electrolysis, for this i need the amount of current required to produce 1 g/sec of hydrogen

Last edited: Nov 16, 2016
2. Nov 16, 2016

### phinds

"2V" is NOT "DC current". It is potential, not current at all. Do you understand Ohm's Law?

Have you done any research on this? If so, what have you found? If not, then go do some.

3. Nov 16, 2016

### Ali Durrani

Ok ok i have mistaken its i am applying a potential of 2 volts and i need to find out the amount of current can you guide me please? i am very weak in electrical stuff

4. Nov 16, 2016

### phinds

You are asking completely the wrong question. You can't specify the amount of current, you have to specify the voltage and then the current will follow from the amount of resistance over which the voltage is applied.

AGAIN, I say, do some research.

5. Nov 16, 2016

### Bystander

6. Nov 16, 2016

### Ali Durrani

Bystander? sir i used faraday but its giving me an answer of a very large amount of current

7. Nov 16, 2016

### Bystander

8. Nov 16, 2016

### Haklesup

Have you figured out how much hydrogen 1 gram is?
have you figured out how many water molecules must be split to get that much H2
What about the surface area and material of the electrodes
Have you defined the concentration of the electrolyte.

It world be far easier to figure it out experimentally but you still need to convert 1g of H2 to a volume at a certain pressure or its going to be hard to measure

9. Nov 17, 2016

### Ali Durrani

The half reaction at cathode ;
4e + 4H2O ------> 2H2 +4OH
this means 1 mole of electron can produce 0.5 mole of Hydrogen gas. now
for example i want to produce 1 gm of h2/sec this means 3600gms in 1 hour
so no of moles is = mass of H2 required/molar mass of H2
so no of moles = 3600/2.02 = 1782.17 moles of H2
Now as i know that 1 mole of electron gives half mole of Hydrogen i need double amount of moles of electrons to get 1 mole of hydrogen
so no of moles of electron = no of moles of H2 x 2
no of moles of electron = 2*1782.17 = 3564.35 moles of electron
as i know that 1 mole of e = 1 F so 3564.35 moles of electron means 3564.35 F
to obtain the charge in columb
3564.35*96485 = 3.44*10^8 columb
now current is I = (3.44*10^8C)/3600s
I = 95529 Amps
WTHH! whats wrong here

10. Nov 17, 2016