What angle should an elctron beam leave an electron gun?

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To determine the optimal angle for a 1kV electron beam with a 1mA current to achieve minimum diameter on a screen 25cm away, specific equations related to beam dynamics and focusing are needed. The original beam diameter is 2mm, but the user is struggling to find relevant equations in their materials. Questions arise regarding the influence of magnetic or electric fields on the beam's trajectory and focusing mechanisms. Clarification on whether lenses are involved in focusing the beam is also sought. Additional details or diagrams could enhance understanding and facilitate problem-solving.
drmerby3737
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1. At what angle should a 1kV electron beam with a total current of 1mA leave an electron gun in order that the cross section of minimum diameter will occur on a screen 25cm away? The original diameter of this beam is 2mm.



2. Cannot find equations in book or notes anywhere.



3. No attempt, just looking for some help maybe in the form of equations please.
 
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drmerby3737 said:
1. At what angle should a 1kV electron beam with a total current of 1mA leave an electron gun in order that the cross section of minimum diameter will occur on a screen 25cm away? The original diameter of this beam is 2mm.



2. Cannot find equations in book or notes anywhere.



3. No attempt, just looking for some help maybe in the form of equations please.


Are there any more details or a diagram available? Why would the e-beam leave the gun at an angle? Are there some magnetic fields or other fields involved? What is doing the focusing?
 
This is all the information that is stated in the question. I asked 5 classmates and no one knows where to begin. In the notes they talk about lenses but it does not specify that is what is doing the focusing.
 
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