What Are Counterexamples for AεB and BεD Leading to AεD?

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Homework Help Overview

The discussion revolves around finding counterexamples to the statement "If AεB and BεD, then AεD," focusing on the relationships between sets A, B, and D, particularly in the context of set membership and nested sets.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • Participants present different counterexamples involving sets and their elements, questioning the notation and definitions used in the examples. There is an emphasis on understanding how elements relate across the sets.

Discussion Status

Multiple counterexamples have been proposed, with participants engaging in clarifying the relationships between the sets. Some express confusion about the original example's notation and seek simpler explanations, while others provide alternative examples that they find easier to understand.

Contextual Notes

Participants note the complexity of the notation used in the examples, which includes sets containing sets, and the implications of membership in these nested structures. There is a recognition that the original example may not be as intuitive as the alternatives provided.

Wildcat
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Homework Statement



Find a counterexample for the following
If AεB and BεD, then AεD.

Homework Equations





The Attempt at a Solution



The answer given is let A={1} B={{1}} and D={{{1}}}
I have not seen this notation before and don't know what it means.
Can someone explain please??
 
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Let's give a different (counter)example: (The highlighting is merely for emphasis.)

Let A={1, 2}

Let B={{1}, {3}, {1, 2}, {1, 2, 4, 8}} ---- You could also write this as: B={{1}, {3}, A, {1, 2, 4, 8}}

Let D={ {{1}, {3}}, {{1, 2, 3}, {1, 2, 4, 8}}, {{1}, {3}, {1, 2}, {1, 2, 4, 8}} }

A is a set whose elements are natural numbers: in this case 1 & 2.

B is a set whose elements are themselves sets: in this case sets of natural numbers, one of which is the set A.

D is a set whose elements are sets of sets. Although the set A is contained in one of the sets of sets, namely set B, which appear in set D, A itself does not appear as one of the elements of set D.

The (counter)example give as the solution is merely a very simple one.
 
SammyS said:
Let's give a different (counter)example: (The highlighting is merely for emphasis.)

Let A={1, 2}

Let B={{1}, {3}, {1, 2}, {1, 2, 4, 8}} ---- You could also write this as: B={{1}, {3}, A, {1, 2, 4, 8}}

Let D={ {{1}, {3}}, {{1, 2, 3}, {1, 2, 4, 8}}, {{1}, {3}, {1, 2}, {1, 2, 4, 8}} }

A is a set whose elements are natural numbers: in this case 1 & 2.

B is a set whose elements are themselves sets: in this case sets of natural numbers, one of which is the set A.

D is a set whose elements are sets of sets. Although the set A is contained in one of the sets of sets, namely set B, which appear in set D, A itself does not appear as one of the elements of set D.

The (counter)example give as the solution is merely a very simple one.

Your counter example is much easier to understand. I still don't know about the one given. Is it saying in A 1 is a natural number, then B is the set {1} then D ugh I don't know? Can you explain that as simply as your counterexample?
 
Wildcat said:
Your counter example is much easier to understand. I still don't know about the one given. Is it saying in A 1 is a natural number, then B is the set {1} then D ugh I don't know? Can you explain that as simply as your counterexample?
They're saying:

A={1}
A is a set whose only element is the number, 1.​

B={ {1} }
B is a set whose only element is the set {1}. You can also say: B is a set whose only element is the set A, because A = {1}

D={ { {1} } }
D is a set whose only element is the set B, which is itself a set containing the set A.​

Yes, it can be somewhat confusing. The main idea here is the the number, 1, is not an element of either set B or set D. set B contains a set. That set contains the number 1.
 
SammyS said:
They're saying:

A={1}
A is a set whose only element is the number, 1.​

B={ {1} }
B is a set whose only element is the set {1}. You can also say: B is a set whose only element is the set A, because A = {1}

D={ { {1} } }
D is a set whose only element is the set B, which is itself a set containing the set A.​

Yes, it can be somewhat confusing. The main idea here is the the number, 1, is not an element of either set B or set D. set B contains a set. That set contains the number 1.


Thank you sooo much! I still like your example better :)
 

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