What Are the Components of Vector C in the Equation A-B+3C=0?

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SUMMARY

The equation A - B + 3C = 0 requires calculating the components of vector C given vectors A and B. Vector A has components (-8.70 cm, 15 cm) and vector B has components (13.2 cm, -6.60 cm). By subtracting vector B from vector A, the resultant vector D is calculated as D = A - B = (-21.90 cm, 21.60 cm). Consequently, the components of vector C are derived from the equation C = -D/3, resulting in C = (7.30 cm, -7.20 cm).

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Homework Statement


vector A has x and y components of -8.70 cm and 15 cm, respectively; vector B has x and y components of 13.2 cm and -6.60 cm, respectively. if A-B+3C=0, what are the components of C?



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The Attempt at a Solution



i can't figure out how to do it
 
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you have vector A and vector B subtract them and whatever you get let's call it D, so you will have D+3C=0=>-D/3=C. Remember keep D in x and y component and then divide it by 3.
 

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