What Are the Correct Calculations for a Geosynchronous Satellite's Orbit?

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Homework Help Overview

The discussion revolves around the calculations related to a geosynchronous satellite's orbit, specifically focusing on the force acting on the satellite and the mass of the planet it orbits. The context involves gravitational forces and orbital mechanics.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculations for the satellite's orbital speed, the force acting on it, and the mass of the planet. There is an emphasis on verifying the equations used and the values substituted into them.

Discussion Status

Some participants have provided feedback on the calculations, questioning the use of specific values and suggesting alternative methods for calculating the force. There is a recognition of discrepancies in the force values, and participants are actively recalculating to ensure accuracy.

Contextual Notes

Participants are working within the constraints of the problem statement, which includes specific values for gravitational constant and satellite parameters. The discussion also highlights the importance of unit conversions, particularly in relation to the period of the satellite's orbit.

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[SOLVED] Circular orbit question...please check answers

Homework Statement


Given: G = 6.67259 × 10^-11 N m^2/kg^2 .
A 956 kg geosynchronous satellite orbits a planet similar to Earth at a radius 201000 km
from the planet’s center. Its angular speed at this radius is the same as the rotational speed of the Earth, and so they appear stationary in the sky. That is, the period of the satelliteis 24 h .

What is the force acting on this satellite? (Newtons)
What is the mass of this planet? (kgs)

I just need help checking my answers and make sure that I am using the correct equations. I would appreciate the help.

Homework Equations


v= (2*pi*R)/T
v= (Sqrt(G * Mcentral))/R; G=6.67259 *10^-11
F=(GmM)/r^2

The Attempt at a Solution


v= (2*pi*R)/T = (2*pi*201,000,000)/86400 = 14617.1 m/s

v= (Sqrt(G * Mcentral)); (v^2 *r)/G=Mcentral
Mcentral= (14617.1^2 * 201,000,000)/(6.67259 *10^-11)= 6.43615 * 10^26 kg

F=(GmM)/r^2
F= [(6.67259*10^-11) * (956) * (6.43615 *10^26)]/(86400^2)=5.49985 *10^9 N
 
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Where did the 86400 come from in your force equation?

Your speed seems fine, and I would probably use F=m\frac{v^2}{r} for the force due to circular motion, which gives 1.016 kN. The mass of the planet is then 643*10^24 kg, as you have.

Recheck your force.
 
The 86400 = 24 hrs in seconds, the period. I also thought that the force was high...I'll recalculate.
 
I also got 1016.21 N when recalculated...thanks
 

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