What are the Cross Products of Vectors AB and AD in Calculus 3?

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SUMMARY

The discussion focuses on calculating the cross product of vectors AB and AD in a Calculus 3 context. The vectors were identified as AB = <4, 2, 3> and AD = <1, -1, 1>. The magnitude of the cross product |AB x AD| was calculated to be √62. Participants sought clarification on the derivation of vector AD, indicating a collaborative effort to resolve misunderstandings in vector calculations.

PREREQUISITES
  • Understanding of vector notation and operations
  • Familiarity with cross product calculations
  • Knowledge of magnitude of vectors
  • Basic concepts of Calculus 3
NEXT STEPS
  • Review the properties of vector cross products
  • Practice calculating magnitudes of vectors
  • Explore vector operations in 3D space
  • Study applications of cross products in physics and engineering
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Students in Calculus 3, educators teaching vector mathematics, and anyone seeking to improve their understanding of vector operations and cross products.

GreenPrint
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Homework Statement



see attachment

Homework Equations





The Attempt at a Solution



i found AB got <4,2,3>
i found AD got <1,-1,1>
i found |ABxAD| got square root of 62

not exactly sure what i am doing wrong thanks for any help
 

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GreenPrint said:

Homework Statement



see attachment

Homework Equations





The Attempt at a Solution



i found AB got <4,2,3>
i found AD got <1,-1,1>
i found |ABxAD| got square root of 62

not exactly sure what i am doing wrong thanks for any help

I'd like to know how you got <1,-1,1> for AD.
 
oh dang thanks man
 

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