What are the forces exerted on a diving board when a person stands on the tip?

  • Thread starter Thread starter PeachBanana
  • Start date Start date
  • Tags Tags
    Board Forces
Click For Summary
SUMMARY

The discussion focuses on calculating the forces exerted on a diving board when a 62 kg person stands at its tip. The force exerted by support B is calculated as F (B) = 607.62 N using the equation F = ma. To find the force at support A, the torque balance equation must be applied, ensuring that the sum of torques is zero due to the absence of rotational acceleration. Additionally, a force balance equation is necessary to confirm that the sum of vertical forces equals zero, reflecting no translational acceleration.

PREREQUISITES
  • Understanding of Newton's second law (F = ma)
  • Knowledge of torque and rotational equilibrium
  • Familiarity with force balance equations
  • Basic principles of static equilibrium
NEXT STEPS
  • Study torque balance equations in static systems
  • Learn about static equilibrium and its applications in physics
  • Explore examples of force balance in various mechanical systems
  • Review detailed calculations involving forces and torques in real-world scenarios
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators and professionals involved in engineering and design of structures subject to static loads.

PeachBanana
Messages
189
Reaction score
0

Homework Statement



Calculate the forces F (A) and F (B) that the supports exert on the diving board of the figure when a 62 kg person stands at its tip. Ignore the weight of the board. Assume that x-axis points upward.

Homework Equations



F = ma

The Attempt at a Solution



F (B) = (62 kg)(9.8 m/s^2) = 607.62 N

F (A) = (x kg)(9.8 m/s^2) = ______ N

I'm having trouble as to what to use for the mass. I was thinking 62 kg but it wouldn't make sense for them to be the same if A is farther away.
 

Attachments

  • DivingBoard.jpg
    DivingBoard.jpg
    7.1 KB · Views: 1,780
Last edited:
Physics news on Phys.org
The only force that is equal to (62 kg)*g is the weight of the person. To solve for the other forces, you need to use the torque balance equation. In other words, use the fact that the sum of torques on the board is 0, since it has no rotational acceleration.

You'll also need to use a force balance equation. The sum of vertical forces on the board should be 0, since it has no translational acceleration.
 

Similar threads

Replies
6
Views
3K
Replies
39
Views
4K
Replies
4
Views
1K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 35 ·
2
Replies
35
Views
4K
Replies
3
Views
7K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 23 ·
Replies
23
Views
2K
  • · Replies 21 ·
Replies
21
Views
2K