What are the integrals for a square with complex number corners?

[jaci55555]

find the integral int(1/z)dz along r for the curve:
square with corners 1+i, -1+i, -1-i, 1-i
traversed clockwise and anti-clockwise

Homework Equations

i know that clockwise will be the -(int) of the anticlockwise

The Attempt at a Solution

the first line = (1-2t)+i it's derivative -2
the second line = -1+i(1-2t) it's derivative -2i
the third line = (-1+2t)-i it's derivative 2
the fourth line = i(2t-1)+1 it's derivative 2i

so integrating each line separately i get:
4x(int[0-1]((2i+4t-2)/(2-4t-4t^2))dt)
= 8(int[0-1](1/(1-2t+2t^2))dt + int[0-1]((2t-1)/(1-2t+2t^2)dt)

now i am just stuck with the integration
please help me complete this

 

[lurflurf]

They will all look like log(*)