What Are the Limits for Calculating the Radial Electric Field Potential?

[chris_avfc]

Homework Statement

Radial component of an electric field near charge 'q'.

E = (1 / 4∏ε) * (q/r^2)

Need to find the potential of this which is done through integrating this and taking the negative answer, i.e.

ΔV = -∫E dr

This is to be along a radial path towards the charge, starting from infinity to r2.

The Attempt at a Solution

So I have

ΔV = - (q/4∏ε) ∫1/r^2 dr

As the charge is constant.
Just unsure on the limits, I'm guessing its ∞ and r2, would that be right?

 

[ehild]

$$\Delta V=V(r)-V(\infty)=-\frac{q}{4\pi \epsilon _0}\int_{\infty}^r{\frac{1}{r^2}dr}$$,

with V(∞)=0


ehild

 

[chris_avfc]

$$\Delta V=V(r)-V(\infty)=-\frac{q}{4\pi \epsilon _0}\int_{\infty}^r{\frac{1}{r^2}dr}$$,

with V(∞)=0


ehild

Awesome, cheers mate. I had my limits the wrong way around.