Medicol
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1. A gene of length 4080 A° has 3120 hydrogen bonds. On one chromatid of one gene, there are 240 nucleotides of adenine, and 40% of total nucleotides are cytosine. Calculate each nucleotide percentage in the gene.
3. Set L be the length of DNA, so L=\frac{N}{2}3.4
we then have N=2400.
Because C_1=G_2=0.4N=960
and A_1=T_2=240
we have A_2+C_2=1200
In a DNA we also have ∑Hbonds=2A+3G=2(A_1+A_2)+3(G_1+G_2)=3120
or 480+2A_2+3G_1+2880=3120
or 2A_2+3G_1=-240
It's an incorrect approach...
Homework Equations
3. Set L be the length of DNA, so L=\frac{N}{2}3.4
we then have N=2400.
Because C_1=G_2=0.4N=960
and A_1=T_2=240
we have A_2+C_2=1200
In a DNA we also have ∑Hbonds=2A+3G=2(A_1+A_2)+3(G_1+G_2)=3120
or 480+2A_2+3G_1+2880=3120
or 2A_2+3G_1=-240


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