What are the points and vector in this plane?

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    Plane Point
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Discussion Overview

The discussion revolves around understanding points and vectors in a specific plane defined by the equation \(y = z\). Participants explore the representation of points in this plane and the corresponding vectors connecting them, while also addressing issues with the clarity of the initial post's notation.

Discussion Character

  • Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant proposes that the vector connecting a general point \((x, y, z)\) to a specific point \((x_0, y_0, z_0)\) is given by \((x - x_0)\mathbf{i} + (y - y_0)\mathbf{j} + (z - z_0)\mathbf{k}\) and is parallel to the plane.
  • Another participant questions the clarity of the notation used in the initial post, specifically the garbled text and the unusual terminology for the plane definition.
  • A different participant suggests that the notation for the unit vectors should be clarified as \(\hat{i}, \hat{j}, \hat{k}\).
  • One participant expresses uncertainty about the meaning of the plane definition \((x, y, z) | y = z\) and speculates that it refers to any point where \(y\) is equal to \(z\).

Areas of Agreement / Disagreement

Participants express confusion regarding the notation and terminology used in the initial post, indicating a lack of consensus on its clarity. There is no agreement on the correctness of the proposed points and vectors, as the discussion focuses more on clarifying the notation.

Contextual Notes

The discussion highlights limitations in the clarity of mathematical notation and terminology, which may affect understanding. The exact implications of the plane definition and the correctness of the proposed points and vectors remain unresolved.

hivesaeed4
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Consider a general point in a plane $${(x, y, z)}$$ and a specific point $${(x_0, y_0, z_0)}$$. The vector

$${(x - x_0)\tmmathbf{i}+ (y - y_0)\tmmathbf{j}+ (z - z_0)\tmmathbf{k}}$$

is parallel to the plane.

Consider the plane $${{(x, y, z,) |y = z}}$$. One point that lies in the plane is the point $${(1, 1, 1)}$$. Find a second point in the plane and the vector that connects them.

So are the below answers correct?

Second point (2,2,2)
Vector= i+j+k
 
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The text is messed up. The line after "The vector" is garbled. "(x−x 0 )\tmmathbfi+(y−y 0 )\tmmathbfj+(z−z 0 )\tmmathbfk"

Also "(x,y,z,)|y=z" is an unusual terminology - what does it mean?
 
mathman said:
The text is messed up. The line after "The vector" is garbled. "(x−x 0 )\tmmathbfi+(y−y 0 )\tmmathbfj+(z−z 0 )\tmmathbfk"

He just meant i hat, j hat, and k hat. ##\hat{i}, \ \hat{j}, \ \hat{k}##
 
Thanks for the clarification scurty. Now as for
Also "(x,y,z,)|y=z" is an unusual terminology - what does it mean?

Well honestly I don't know my self but I'm supposing it means any point where y is equal to z.
 

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