What Are the Tensions in the Two Cables at Point C?

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SUMMARY

The discussion focuses on calculating the tensions in two cables, AC and BC, at point C, with the final answers being 120.1N for AC and 156.3N for BC. The angles of the cables were determined using trigonometric functions, specifically tan-1, yielding angles of 38.66 degrees for AC and 53.13 degrees for BC. The equilibrium of forces was established by setting the x-components of the tensions equal and summing the y-components to 200N. The solution involves solving two equations derived from these conditions.

PREREQUISITES
  • Understanding of trigonometric functions, specifically tangent and inverse tangent.
  • Knowledge of static equilibrium principles in physics.
  • Ability to solve systems of equations involving tension forces.
  • Familiarity with vector components in two-dimensional force analysis.
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  • Study the principles of static equilibrium in more depth.
  • Learn how to apply trigonometric identities in force analysis.
  • Explore vector resolution techniques for forces in physics.
  • Practice solving systems of equations related to tension and forces in various configurations.
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This discussion is beneficial for physics students, engineers, and anyone involved in mechanics or structural analysis, particularly those dealing with cable tension problems.

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Homework Statement



2 cables are tied together at C as shown. Determine the tension in AC and BC.
(ans: 120.1N, 156.3N)

tutorial2_7.jpg


Homework Equations





The Attempt at a Solution



tan-1 4/5 = 38.66
tan-1 4/3 = 53.13

100/tan 38.66 = ACx
ACx = 124.99

AC = sqrt(124.99^2 + 100^2)
AC = 160 (wrong)
 
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If T1 is the tension in AC and T2 that of BC, then x-components of T1 and T2 cancel each other. Hence

T1*cos(38.66) = T2*cos(53.13) ...(1)

Similarly y-components of tensions add up to 200 N.

Solve the two equations and find T1.
 

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