Ravian
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(AB+1)/(ABC+A+C)=0.138, Find values of A,B,C.
The discussion revolves around finding the values of the variables A, B, and C in the equation (AB+1)/(CBA+A+B)=0.138. Participants explore the implications of having one equation with three unknowns, discussing potential assumptions and methods for solving the equation.
Participants generally agree that additional information or equations are needed to find specific values for A, B, and C. However, there are competing views on how to approach the problem, with some suggesting assumptions and others emphasizing the limitations of the single equation.
Participants express uncertainty regarding the assumptions needed to reduce the number of variables and the implications of different interpretations of the equation.
Isolate all terms with an “A” to one side, then factor out the “A”. would be a good way to approach this.Ravian said:You are right but this is the way it is. I guess we need to make assumptions to reduce the number of variables. I tried AB=X and some other but it is not working. Fortunately I know it is solvable but I don't know how.
Ravian said:You are right but this is the way it is. I guess we need to make assumptions to reduce the number of variables. I tried AB=X and some other but it is not working. Fortunately I know it is solvable but I don't know how.
Ravian said:(AB+1)/(ABC+A+C)=0.138, Find values of A,B,C.