What Calculations Determine the Dynamics of a Ball in Vertical Circular Motion?

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SUMMARY

The discussion focuses on the dynamics of a ball in vertical circular motion, specifically analyzing a 0.1 kg ball with a radius of 0.8 m and an initial speed of 6 m/s at the top of the circle. The total mechanical energy is calculated as 3.564 J, with the speed at the lowest point determined to be 8.2 m/s. Tension forces are evaluated, yielding 3.52 N at the top and 5.48 N at the bottom, although the latter requires adjustment based on the tangential speed at the lowest point. The principles of conservation of energy and gravitational potential energy are emphasized throughout the calculations.

PREREQUISITES
  • Understanding of gravitational potential energy and kinetic energy
  • Familiarity with Newton's laws of motion
  • Knowledge of circular motion dynamics
  • Ability to apply conservation of energy principles
NEXT STEPS
  • Study the equations of motion for circular dynamics in physics
  • Learn about the effects of tension in circular motion scenarios
  • Explore energy conservation in non-conservative systems
  • Investigate the impact of varying mass and radius on circular motion outcomes
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the mechanics of circular motion and energy conservation principles in dynamic systems.

thugg
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Circular Motion...

Ok, you have a ball being swung vertically in a circle. Mass=0.1kg, radius=0.8m, speed at top = 6m/s , and this occurs 0.2m off the ground. using the floor as the zero point for gravitational potential energy, what is the total energy. Determine the speed at the lowest point. Determine the tension at the top and bottom. The ball reaches the top of the circle once before the thread breaks, when the ball is at the lowest point of the circle. Determine the horizontal distance it travels before hitting the floor.

Any help would be great.


Edit: to make it not appear as though I just want some answers...i have tried this and got these answers, maybe you can tell me where i went wrong...


total energy = pe + ke = .5*.1*36 + 9.8*.1*1.8= 3.564

speed at lowest point... 0.2*9.8*0.1 + 0.5*0.1*v squared = 3.564 v = 8.2

tension at top... 0.1*36/0.8 - 0.1*9.8 = 3.52
tension at bottom... 0.1*36/0.8 + 0.1*9.8 = 5.48
 
Last edited:
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Assuming conservation of energy holds, then PE1 + KE1 = PE2 + KE2, or [itex]\Delta[/itex]KE = [itex]\Delta[/itex]PE.

The gravitational potential energy increases with height, so minimum velocity and kinetic energy occur at the top of the arc, and max. velocity (speed) and KE occur at the bottom.

The total energy seems right and the speed at the bottom.

Tension at top seems correct, but tension at bottom needs to use the velocity (tangential speed) at the bottom.
 

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