What Determines Maximum Voltage in an RL Circuit with AC Power?

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SUMMARY

The maximum voltage across a resistor (R) and inductor (L) in a series AC circuit can be determined using impedance calculations. Given a resistor of 100 ohms and an inductor with a reactance of 62.8 ohms at 10 kHz, the total impedance (Z) is calculated as 118.08 ohms using the formula Z^2 = R^2 + XL^2. When a 150-volt AC source is applied, the current is 1.27 A, resulting in a voltage drop of 127 V across the resistor and 79.76 V across the inductor. The sum of the voltages exceeds the source voltage, but their squares conform to the principle of conservation of energy.

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  • Familiarity with impedance and reactance calculations
  • Knowledge of Ohm's Law
  • Ability to apply Pythagorean theorem in electrical contexts
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I know this is a simple question but I can't quite figure out how to do this in a combined circuit:

Find the maximum voltage across a resistor R and inductor L with an AC power source of V0sin(wt). (Note: the resistor is in series with the inductor) I'm trying to figure out the total max voltage and the max voltage for each (if that's even possible).

I'm a bit new to AC circuits so I don't really know how to handle things when dealing with them, so any extra tips outside of how to go about this problem would help immensely.
 
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If you have an inductor and know its inductance you can work out its reactance at a known frequency by this formula:
XL = 2 * pi * F * L
eg 10000 hz and 1 mH, ZL =62.8 ohms

If this is put in series with a 100 ohm resistor, what would be the resulting impedance?

The easy way is to draw (or imagine) a triangle with R horizontal and XL vertically upward from the end of the resistive line (so it is a right angled triangle) and then draw a hypotenuse on these lines to make a triangle.
This hypotenuse represents the resultant impedance.

Using Pythagoras, Z^2 = R^2 + XL^2
so Z^2 = 100^2 + 62.8^2
from this Z= 118.08 ohms

So if you put 150 volts across the series combination at 10000 Hz the current would be
150 / 118.08 or 1.27 A

This current flows through the coil and the resistor.
Voltage across the resistor = I R = 1.27 * 100 = 127 V
Voltage across the coil = 1.27 * 62.8 = 79.76 V

Note that these add up to more than 150 volts, but their squares add up to the square of 150.
 
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