What Determines the Charge of an Object in Electrostatic Induction?

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A body maintains a constant negative electrostatic charge by having the same excess of electrons. In a scenario involving electrostatic induction, a negatively charged rod A induces a positive charge on rod B, which then transfers this positive charge to object C upon contact. The confusion arises from the understanding that induction leads to a net positive charge on B, allowing it to attract electrons from C when they touch. The discussion clarifies that induction differs from conduction, as it alters the charge distribution without direct electron transfer until contact occurs. Ultimately, the charge on object C becomes positive because it is influenced by the net positive charge of rod B.
MIA6
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1. A body will maintain a constant negative electrostatic charge if the body
1) Maintains the same excess of electrons. 3) Continuously receives more electrons than it loses.
I chose 3) but I think both choices work. However, the correct answer is 1), I don’t why 3) is wrong.

2. Negatively charged rod A is used to charge rod B by induction. Object C is then charged by direct contact with rod B. The charge on object C
1) is positive 3) is negative.
I chose 3) because when negative charged rod A moves close to one end of rod B, the electrons in rod B would gather at the other end, so left the opposite end all positive. After that, when C comes to contact with rod B, it depends on which end it touches. I am little confused. If it touches the negative end, then C becomes negative; vice versa. But the answer was 1).

thanks for help.
 
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MIA6 said:
1. A body will maintain a constant negative electrostatic charge if the body
1) Maintains the same excess of electrons. 3) Continuously receives more electrons than it loses.
I chose 3) but I think both choices work. However, the correct answer is 1), I don’t why 3) is wrong.

2. Negatively charged rod A is used to charge rod B by induction. Object C is then charged by direct contact with rod B. The charge on object C
1) is positive 3) is negative.
I chose 3) because when negative charged rod A moves close to one end of rod B, the electrons in rod B would gather at the other end, so left the opposite end all positive. After that, when C comes to contact with rod B, it depends on which end it touches. I am little confused. If it touches the negative end, then C becomes negative; vice versa. But the answer was 1).

thanks for help.


1. The operative word is Constant. Unchanging. Stays the same.

2. If B's charge is affected by induction, it will be net positive and then it will be a sink for electrons when it is touched by C, imparting a net positive to C as well.
 


LowlyPion said:
2. If B's charge is affected by induction, it will be net positive and then it will be a sink for electrons when it is touched by C, imparting a net positive to C as well.

But induction is not conduction, why B will be net positive? If B is positive orginally, it's still positive; if it's negative, it will still be negative.
 


MIA6 said:
But induction is not conduction, why B will be net positive? If B is positive orginally, it's still positive; if it's negative, it will still be negative.

A is negative. Induction makes B net positive. Touching neutral C to B makes C net positive too.
 


LowlyPion said:
A is negative. Induction makes B net positive. Touching neutral C to B makes C net positive too.

If B is net positive, where did some electrons in B go?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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