What Determines the Maximum Height for Water Flow in a Faucet?

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Homework Help Overview

The discussion revolves around fluid mechanics, specifically the behavior of water flow in a plumbing system. The original poster presents a problem involving gauge pressure and the maximum height of a faucet in relation to water flow from a pressurized line.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between gauge pressure and height in a fluid system, questioning how static pressure affects flow when a faucet is open versus closed.
  • Some participants attempt to apply the hydrostatic pressure formula, while others express confusion about the implications of pressure when the faucet is open.
  • There is a discussion about the dimensions of the equations being used and the clarity of variable notation.

Discussion Status

Participants are actively engaging with the problem, with some offering insights into the relationship between pressure and height. There is a mix of understanding and confusion, particularly regarding how to apply the pressure calculations to determine the maximum height for water flow.

Contextual Notes

Some participants note the importance of distinguishing between static and dynamic pressure, and there is a recognition that the problem does not require detailed hydrodynamic analysis, focusing instead on the balance of pressure and height.

alaa410
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The main water enters a house on the first floor. the line has a gauge pressure of 1.9x10^5Pa
a) A faucet on the second floor 6.50 meters above the first floor is turned off. what is the gauge pressure of this faucet? b)how high could a faucet be before no water would flow from it even if the faucet were open.

iv figured the first part is solved with P2= p1+densitygh

but I am very unclear about what would matter with the faucet being open in part two please help :)
 
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alaa410 said:
The main water enters a house on the first floor. the line has a gauge pressure of 1.9x10^5Pa
a) A faucet on the second floor 6.50 meters above the first floor is turned off. what is the gauge pressure of this faucet? b)how high could a faucet be before no water would flow from it even if the faucet were open.

iv figured the first part is solved with P2= p1+densitygh

but I am very unclear about what would matter with the faucet being open in part two please help :)
When water is not flowing, the pressure is 'static'. When a liquid is flowing through a pipe, there is a pressure drop associated with the viscosity of the liquid.

In a vertical pipe, in order for the fluid to flow out the upper end, the pressure must exceed the static head ρgh. So what is the gauge pressure of the liquid at the top end of an open vertical pipe when the liquid does not flow? Then relate that to p1 + ρgh, and solve for h.
 
gh=p1+pgh?
 
alaa410 said:
gh=p1+pgh?
That can't be right because it mixes dimensions. LHS is accn*distance = L2T-2. RHS is pressure, ML-1T-2.
Also, it's confusing to use p1 for a pressure and p for a density. ρ for density would be better.
To answer your original question, obviously there can be no flow if the faucet is closed. With the faucet open, there will be some flow as long as the pressure supplied overcomes the head of water in the up pipe. The rate of flow will depend on by how much extra pressure there is (and a few other things). The wording of the question is intended to make it clear that they don't care about the rate of flow, so it is not a hydrodynamics question. All they are asking for is what supply pressure will just balance the head of water.
 
its asking how high the faucet should be so that no water would reach it from the pressure gauge at the bottom of the house that much i understand. but I am still not getting how i would solve for that. i got the pressure of water coming out of the faucet at 6.5 but i don't see how that number will help me find part b
 
alaa410 said:
its asking how high the faucet should be so that no water would reach it from the pressure gauge at the bottom of the house that much i understand. but I am still not getting how i would solve for that.
At the height at which no water would come out, the water pressure would be, what?
i got the pressure of water coming out of the faucet at 6.5 but i don't see how that number will help me find part b
It doesn't, but the same formula does.
 
p1/ρg=h ? some one give me a solution for gods sake :p
 
well look at that... it worked haha thanks guys :D
 

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