What Determines the Period of Oscillation in an LC Circuit?

[snipaj9696]

A series LC circuit contains a 100 mH inductor, a 36.0 mF capacitor and a 12 V battery. The period of the electromagnetic oscillations in the circuit is



1. 0.0227 s.

2. 1750 s.

3. 105 s.

4. 2.26 s.

5. 0.376 s.


f= 1/ 2*π *√L *C

L =100mH
C= 36uF

so,,f = 2.65

T = 1/f = 0.376S Is this correct?

Thanks in advance!

 

[kamerling]

I don't think the correct answer is there at all. The correct equation for the frequency
is: f = \frac {1} {2 \pi \sqrt{L C}}.
if you type it in ascii you should type f = 1 / (2 * pi * √(L*C)) to prevent misunderstanding. If I substitute L = 0.1 H and C = 36 * 10^(-6) F, I get f = 83.9 Hz and T = 0.0119 s

 

[alphysicist]

In the original problem statement you have that the capacitance is 36 milliFarads, but later in your post you state that the capacitance is 36 microFarads. If the capacitance is 36 mF, then I believe your answer is correct.

 

[snipaj9696]

I apologize the the m in the mF for 36mF is the greek letter Mu (10E-6). With that said is my answer correct?

 

[snipaj9696]

WAIT! IT IS 36mF.. The m is not Mu!

 

[Kurret]

may I ask what causes this electromagnetic oscilliation? never heard of it before...

 

[Snazzy]

Well, you had listed it as uF at the very bottom, not mF.

An alternating voltage source causes the oscillation.