What direction of r vector would decrease the potential energy most rapidly?

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SUMMARY

The discussion focuses on the gravitational force acting on a mass, m, located at a position vector r = (x, y, z) due to another mass, M, at the origin. The gravitational force is defined as F(r) = (-GmM/||r||^3)(r), with GmM set to 1 for simplification. The direction that decreases potential energy most rapidly is along the vector pointing towards the origin, as indicated by the relationship F(r) = -∇V(r), where V(r) = -1/r. The discussion also explores the implications of different potential functions, specifically V(r) = r and V(r) = ln r, on the nature of the force field.

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  • Understanding of gravitational force and potential energy concepts
  • Familiarity with vector calculus, specifically gradient and divergence
  • Knowledge of the mathematical representation of forces in physics
  • Basic understanding of potential energy functions and their implications
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  • Study the derivation of gravitational force from potential energy functions
  • Learn about vector calculus operations such as gradient (∇) and divergence
  • Explore different forms of potential energy functions and their corresponding force fields
  • Investigate the implications of varying gravitational constants in force equations
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Minihoudini
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Homework Statement


Consider a point mass, M, at the origin and a mass, m, at the point r(vector)=(x,y,z). The gravitational force on m is F(r)= (-GmM/||r||^3)(r). For simplicity, let's set GmM=1. Note that this force is directed towards the origin. the gravitational potential is a real valued function of ||r||=r given by V(r)=-1/r

a)what direction from r=(x,y,z) would decrease the potential energy most rapidly?
b)show that F(r)=-delta V(r). what does this say about the force?
c) if the force and the potential are related as in part b, what type of a force field would we have if V(r)=r if V(r)=ln r?

Homework Equations





The Attempt at a Solution



we first originally thought the ||r||^3 was a typo of ||r||^2. So we just simply made the equation F(r)=-1/||sqrt(x^2+y^2+z^2)||^2 * (x,y,z). This becomes really ugly very quickly. We would also take the inverse since that would be the rate of decrease.
 
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Minihoudini said:

Homework Statement


Consider a point mass, M, at the origin and a mass, m, at the point r(vector)=(x,y,z). The gravitational force on m is F(r)= (-GmM/||r||^3)(r). For simplicity, let's set GmM=1. Note that this force is directed towards the origin. the gravitational potential is a real valued function of ||r||=r given by V(r)=-1/r

a)what direction from r=(x,y,z) would decrease the potential energy most rapidly?
b)show that F(r)=-delta V(r). what does this say about the force?
c) if the force and the potential are related as in part b, what type of a force field would we have if V(r)=r if V(r)=ln r?

Homework Equations



The Attempt at a Solution



we first originally thought the ||r||^3 was a typo of ||r||^2. So we just simply made the equation F(r)=-1/||sqrt(x^2+y^2+z^2)||^2 * (x,y,z). This becomes really ugly very quickly. We would also take the inverse since that would be the rate of decrease.
The magnitude of the force vector, \vec{F}(\vec{r}) is given by \displaystyle \left\|\vec{F}(\vec{r})\right\|=\frac{GmM}{r^2}, with \vec{F}(\vec{r}) directed toward the origin.

Thus \vec{F}(\vec{r}) can be written as

\displaystyle \vec{F}(\vec{r})=-\frac{GmM}{r^2}\hat{r}
\displaystyle =-\frac{GmM}{\left\|\vec{r}\right\|^3}\vec{r}​
 

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