What Distance Must a Rock Fall to Double Its Speed?

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SUMMARY

The discussion centers on calculating the distance a rock must fall to double its speed after falling 5 meters. The relevant equations are gravitational potential energy (GPE = mgh) and kinetic energy (Ke = 1/2 mv²). The relationship between velocity and height is established as v ∝ h½, leading to the conclusion that to achieve a speed of 2v, the height must be increased significantly. The solution involves equating the two energy equations to find the required height.

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Homework Statement


After falling 5m a rock has a velocity of v. What is the total distance the rock must fall to get a speed of 2v?


Homework Equations


GPE=mgh
Ke=1/2mv^2

The Attempt at a Solution


Should I set both equations equal to each other? I'm not even sure how to begin this one.
 
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You can do it that way. Note that v = (2*g*h)½

If v ∝ h½ ...

... how much then do you need to increase the height to get a doubling of speed?
 

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