- #1
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Homework Statement
2n
Ʃ (k)
k=1
The Attempt at a Solution
2n
Ʃ (k) = 2n(2n+1)/2 (This is just a shot in the dark.)
k=1
Sure. If you've shown the sum from 1 to n of k is n*(n+1)/2, then the sum to 2n is just 2n*(2n+1)/2. It's just substitution.Homework Statement
2n
Ʃ (k)
k=1
The Attempt at a Solution
2n
Ʃ (k) = 2n(2n+1)/2 (This is just a shot in the dark.)
k=1
So would this work too?Sure. If you've shown the sum from 1 to n of k is n*(n+1)/2, then the sum to 2n is just 2n*(2n+1)/2. It's just substitution.
Sure. Same thing.So would this work too?
2n+1
Ʃ (k) = (2n+1)((2n+1)+1)/2
k=1
[tex] \sum_{k=1}^N k = \frac{N(N+1)}{2},[/tex]Homework Statement
2n
Ʃ (k)
k=1
The Attempt at a Solution
2n
Ʃ (k) = 2n(2n+1)/2 (This is just a shot in the dark.)
k=1