Does a di/dt<0 mean an increasing current moving from a lower potential to a higher potential (if we define the direction of current to be the flow of the positive charges)? Similar question with negative current i.e.; dq/dt<0.
You do realise that di/dt represents the slope or tangent on a graph?
It may help to talk of negative going currents (negative di/dt) and positive going currents (positive di/dt) since there may also be negative currents (against the chosen circuit direction) and positive currents (with the chosen circuit direction).
So the slope of a negative (or positive) current may itself be negative or positive.
Of course the current may also be zero, especially if alternating.
Yes I do of course, it's also the very reason that I'm having conflicting ideas. In the context of calculus (at least from how I knew it), a negative dq/dt would mean that there are decreasing charges as time goes but when the textbook says negative dq/dt also means charges moving in the opposite direction (whatever that direction maybe?) then things get a little perplexing for me. What does this time derivative actually mean? I'm sorry this might sound like a silly question.