What does that substitution do to the integral?What is the resulting integral?

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SUMMARY

The integral of the function a*ln(b/(b - cx)) - kx can be approached by separating it into two parts: a*INT(ln(b/(b-cx)) dx) and -k*INT(x dx). The second integral simplifies to -k*x^2/2. To solve the first integral, it is essential to utilize the properties of logarithms and consider the substitution y = ln(x), which suggests a transformation for x that simplifies the integration process. Mastery of basic logarithmic properties is crucial for successfully evaluating the integral.

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Homework Statement



Find the integral of:

[a*ln(b/(b -cx)) - kx] dx

Where all a,b,c,k are constants and x is the variable.

Homework Equations



The Attempt at a Solution


Rewrote is:
a*INT(ln(b/(b-cx)) dx) - k*INT(x dx)

I don't know how to solve the first part, (the second integral I know is kx^2/2)

Thank you for your help.
 
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I don't know this for you is helpful or not ?

You can check it out form this site.:smile:

http://www.tutorvista.com/math/integral-of-log-x
 
Last edited by a moderator:
You started attack and you have to continue.

∫a*(ln(b/(b-cx)) dx) = a*∫ln(b/(b-cx) dx

You have to remember basic property of logs! You can do this if you can do ∫ ln(b - cx) dx .

And you can do that if you can do ∫ln x dx .

If y = ln x , what does x = ?

What substitution for x does that suggest?
 

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