What Does the Scale Read in Different Elevator Scenarios?

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Homework Help Overview

The discussion revolves around a physics problem involving a person standing on a scale in an elevator, exploring how the scale reading changes under different conditions: at rest, accelerating upward, and accelerating downward. The subject area includes concepts of weight, force, and acceleration in the context of classical mechanics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the expected scale readings under various elevator conditions, questioning the implications of acceleration on weight readings. Some express uncertainty about the necessary formulas and units, while others clarify the relationship between weight and mass.

Discussion Status

There is an ongoing exploration of the problem, with some participants providing insights into the physics concepts involved. Questions about the formulas and units are raised, indicating a collaborative effort to clarify understanding. No explicit consensus has been reached regarding the application of the formulas.

Contextual Notes

Participants mention the potential confusion surrounding units of mass in the US system, specifically referencing the slug. There is also a note about the urgency of the original poster's situation, as they are preparing for a test.

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Homework Statement


A 192 lb person stands on a scale in an elevator. What does the scale read
a. When the elevator is at rest.
b. when the elevator is accelerating up at 4ft/sec^2
c. when elevator is accelerating down at 3ft/sec^2


Homework Equations





The Attempt at a Solution



Im not really sure how to do this, can someone help me and show the formulas as well so I can learn it? Thanks
 
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When the elevator is at rest, the scale will read 192 pounds.
When it is accelerating upward, it will read higher because you not only have the usual mg force pressing the person down but also the ma force necessary to accelerate him upward.

This problem has some messy units - be careful with them. It will be quite difficult to figure out the mass. I'm just old enough to remember that when we had pounds the unit of mass was the "slug". Not joking! Maybe convert everything into metric units?
 
Last edited:
The unit of mass in the US system of measure, is still the slug. 1 slug weighs about 32 pounds : W=mg, where m is in slugs, g is 32ft/sec^2, and W is in pounds.

Nofinga911: What have you tried so far? The formulas will not mean much without your initial attempt.
 
PhanthomJay said:
The unit of mass in the US system of measure, is still the slug. 1 slug weighs about 32 pounds : W=mg, where m is in slugs, g is 32ft/sec^2, and W is in pounds.

Nofinga911: What have you tried so far? The formulas will not mean much without your initial attempt.
Thats just it, I don't know the formulas...It would help me if I saw it done by someone else with the formulas this way I have some time to studyit before my test tomorrow..it was one of two out of the 20 questions I was unable to get. I would be able to break the formula down if I saw it done.
 
The formulas you need are F = mg and F = ma.
Yes, let us see you put the numbers in and do some multiplying!
Do you have the number for g in ft/s^2 ?
 
The problem statement said that this was a 192 lb person, which means that we can assume that at rest on the surface of the earth, this person weight 192 lb.

Delphi51, how do you figure that for the elevator at rest, the scale will read 10 lb? Why not 192 lb?

By the way, Delphi51, I think you probably meant to say W=mg and F=ma, did you not?
 
Terribly sorry - I meant to type 192! That must have been very confusing.

What is the difference between F = mg and W = mg?
Weight is the Force of gravity so either letter should be okay.
The two forces must be added to get the answers.
 
What is the difference between F = mg and W = mg?

The difference, as I see it, is that when you write F = mg and F = ma, there is a natural equivalence implied that therefore mg = ma and therefore g = a.
 

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