What does time=0 represent in kinematics

Click For Summary
SUMMARY

In kinematics, time t=0 is defined as the moment just before a ball is released, marking the initial conditions of motion. At this point, the ball has the initial velocity imparted to it and experiences no vertical velocity due to gravity. In projectile motion, when a ball is thrown horizontally, it has zero vertical velocity and a non-zero horizontal velocity at t=0. This definition allows for clear calculations of motion, as gravity only affects the ball's trajectory after t=0.

PREREQUISITES
  • Understanding of kinematics principles
  • Familiarity with projectile motion concepts
  • Basic knowledge of velocity and acceleration
  • Comprehension of the effects of gravity on motion
NEXT STEPS
  • Study the equations of motion in kinematics
  • Learn about the effects of gravity on projectile motion
  • Explore the concept of initial velocity in various motion scenarios
  • Investigate the role of air resistance in projectile trajectories
USEFUL FOR

Students of physics, educators teaching kinematics, and anyone interested in understanding the principles of motion and projectile dynamics.

Talha
So basically i am confused about time 0 in terms of kinamatics graphs
Lets say i throw a ball upwards so what does time t=0 represent, the time after which the ball is released or the time at which ball is about to be released?
Secondly in projectile motion if i throw a ball horizontally at a height then time zero has zero vertical velocity but a non zero horizontal velocity, why is that(considering the first option that it represents time after ball is released so it must have some vertical velocity even in points due to 9.8m/s^2 acceleration)?
 
Physics news on Phys.org
Typically t=0 is chosen to be the point where the ball is released. The velocity at t=0 is then the initial velocity you give the ball, unaffected by gravity.
The velocity for t>0 is affected by gravity.

Keep in mind that this choice is completely arbitrary. You can define that the ball is released at t=6436.83 s. Then gravity only affects the velocity for t>6436.83 s. It doesn’t change the motion of the ball, it just makes the calculation a bit more complicated.
 
Normally, the complete statement would be "t represents the time in seconds after the ball is released".

So t=0 is when the ball is about to be released and anything >0 is when the ball will have vertical velocity. Since this is the last instant where the ball is still in contact with your hand, this is the initial velocity given to the ball. Afterwards, it will experience acceleration/decelleration due to net force from external factors (air resistance and gravity)
 
Talha said:
So basically i am confused about time 0 in terms of kinamatics graphs
Lets say i throw a ball upwards so what does time t=0 represent, the time after which the ball is released or the time at which ball is about to be released?

The first case is just before the ball is released.
The second case is just after the ball is released.

In the limit (eg when "just before" or "just after" means an infinitely small amount of time) these are the same thing.

Secondly in projectile motion if i throw a ball horizontally at a height then time zero has zero vertical velocity but a non zero horizontal velocity, why is that(considering the first option that it represents time after ball is released so it must have some vertical velocity even in points due to 9.8m/s^2 acceleration)?

It's so soon after release that the vertical velocity might as well still be zero.
 

Similar threads

  • · Replies 49 ·
2
Replies
49
Views
4K
  • · Replies 17 ·
Replies
17
Views
18K
Replies
5
Views
1K
  • · Replies 60 ·
3
Replies
60
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
6K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
6
Views
1K
Replies
5
Views
5K
  • · Replies 38 ·
2
Replies
38
Views
4K