What Factors Determine the Maximum Allowable Force on a Wooden Beam?

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SUMMARY

The discussion focuses on determining the maximum allowable force (P) on a wooden beam before failure, utilizing the relationship between shear and normal stress. Participants emphasize the importance of resolving force P into components along and normal to the beam's end, applying the factor of safety based on failure stresses. The conversation highlights the confusion regarding the distance 'b' and the correct resolution of force components, specifically addressing the calculations of Pcos30 and Psin30 versus P/2cos30 and P/2sin30.

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Homework Statement


Finding the maximum allowable force P before failure

Homework Equations


Shear /normal stress = Force / Area

The Attempt at a Solution


I know that I can resolve the force P to be along and normal to the end of the wooden beam to find the respective forces separately,applying factor of safety, from the failure stresses given and therefore, determine which P is lower which shall be the maximum allowable P. However, I do not see there the distance b come into play. Am i missing something?
 

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Can you show how you "resolved" P?
 
Pcos30 will be my shear force and Psin30 will be my normal force to the end of the beam.
 
Don't you mean P/2cos30 and P/2sin30?
 

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