What Factors Increase the Acceleration on a Spinning Wheel?

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Homework Statement


The magnitude of the acceleration of a point on a spinning wheel is increased by a factor of 4 if:
A) the magnitues of the angular velocity and the angular acceleration are each multiplied by a factor of 4
B) the magnitues of the angular velocity is multuplied by a factor of 4 and the angular acceleration is not changed
C) the magnitues of the angular velocity and the angular acceleration are each multiplied by a factor of 2
D) the magnitues of the angular velocity is multiplied by a factor of 2 and the angular acceleration is not changed
E) the magnitues of the angular velocity is multiplied by a factor of 2 and the magnitudeof the angular acceleration is multiplied by a factor of 4

answer is E

Homework Equations





The Attempt at a Solution



Okay i tried working back from this and must be doing something wrong,

I start with Aradial = v^2/r = rω^2
and Atangential = rα

I rearange for A = Aradial + Atangentail (as vectors)

which is = r√α^2 + ω^4

subbing in 4 and 2 i get r√32
 
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You have interpreted "acceleration" in the question to mean the total acceleration.
For circular motion, radial acceleration (##\small{\ddot r}##) is zero - so you are summing the tangential and centripetal acceleration.

So ##a=r\sqrt{\omega^4+\alpha^2}##

So far so good - but
subbing in 4 and 2 i get r√32
...what did you put 4 nd 2 into and why?

Consider, multiplying angular velocity by 2 means that where you see a ##\omega## before, you put a ##2\omega##.

Working in reverse is a good idea.
You need to put ##a_{new}=4a=4r\sqrt{\omega^4+\alpha^2}##... work out how that 4 fits against the angular terms.
 
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bennyq said:
Okay i tried working back from this and must be doing something wrong,

I start with Aradial = v^2/r = rω^2
and Atangential = rα

I rearange for A = Aradial + Atangentail (as vectors)

which is = r√α^2 + ω^4

subbing in 4 and 2 i get r√32

|a| = r√(α24) ,Now when you put αnew=4α and ωnew =2ω ,you get r√(16(α24)) = 4r√(α24)

Hence option E is correct.
 
ohhh of course.. thanks
 
I think your mistake is that you are substituting values when you should be substituting in ratios.