What Force Accelerates a Sled on Snowy Ground?

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SUMMARY

The discussion centers on calculating the force required to accelerate a sled of mass 13.4 kilograms on snowy ground, considering both static and kinetic friction coefficients. The user initially calculated the force using the formula \( F = ma \) and obtained 36.046 N for an acceleration of 2.69 m/s². However, they overlooked the need to account for the kinetic friction force, which is necessary to determine the total force required for acceleration. The correct approach involves adding the frictional force to the calculated force to find the total force needed.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion (F = ma)
  • Knowledge of friction coefficients (static and kinetic)
  • Ability to perform basic calculations involving mass, acceleration, and force
  • Familiarity with free body diagrams and force analysis
NEXT STEPS
  • Calculate the kinetic friction force using the formula \( F_{friction} = \mu_k \times N \), where \( N \) is the normal force.
  • Learn how to draw and analyze free body diagrams for various physical scenarios.
  • Explore the effects of different surface materials on friction coefficients.
  • Study the principles of dynamics in relation to sledding and other forms of motion on inclined or flat surfaces.
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and dynamics, as well as educators looking for practical examples of force calculations involving friction.

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Homework Statement


A sled of mass 13.4 kilograms is pulled along flat snow-covered ground. The static friction coefficient is 0.334, and the kinetic friction coefficient is 0.111.
I solved both part a and b, but I am having trouble with part c.
c. Once moving, what force is needed to accelerate the sled 2.69 meters per second per second?



Homework Equations


am=f
u=f/n


The Attempt at a Solution



Im confused on how to do this.
So Its asking for the force pushing the sled forward. Using the formula am=f
if i plug in acceleration and the mass i get 13.4x2.69=36.046, but it said it was wrong.
Am I missing something? Do I need to factor in frictional force?
Would I add 14.6 to 36.046? 14.6 is the force needed to push the object at a constant velocity.
 
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mmoran said:

Homework Statement


A sled of mass 13.4 kilograms is pulled along flat snow-covered ground. The static friction coefficient is 0.334, and the kinetic friction coefficient is 0.111.
I solved both part a and b, but I am having trouble with part c.
c. Once moving, what force is needed to accelerate the sled 2.69 meters per second per second?



Homework Equations


am=f
u=f/n


The Attempt at a Solution



Im confused on how to do this.
So Its asking for the force pushing the sled forward. Using the formula am=f
if i plug in acceleration and the mass i get 13.4x2.69=36.046, but it said it was wrong.
Am I missing something? Do I need to factor in frictional force?
Would I add 14.6 to 36.046? 14.6 is the force needed to push the object at a constant velocity.

Do a freebody diagram of the accelerating sleigh. What are the forces acting on the sleigh? What do they necessarily sum to?

AM
 

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