What Force must be exerted on the trolley for constant speed?

[chwala]

Homework Statement

See attached.

Relevant Equations

Mechanics

My question is on the highlighted part in red.

For the first part i have,

$F_{parallel} = 900 \cos 82^0 = 125.3N$

For the second part, i have

$F= \dfrac{125.3}{\cos 15^0} = 129.7 N ≈130N$

 

[TSny]

For the first part i have,

$F_{parallel} = 900 \cos 82^0 = 125.3N$

For the second part, i have

$F= \dfrac{125.3}{\cos 15^0} = 129.7^0 N ≈130N$

Those answers look right to me. (I guess there is no friction). However, based on what you've written, we can't tell if you thought through it correctly.