What Happens to Primary Voltage if 8V is Applied to Secondary Coil?

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SUMMARY

The discussion centers on the behavior of an ideal transformer when an 8V input is applied to the secondary coil. Given a primary voltage of 120V and a secondary voltage of 6V, the relationship between the voltages and turns is defined by the equation v1/v2 = n1/n2. By applying this formula, the calculated primary voltage when 8V is applied to the secondary coil is 160V, confirming the straightforward nature of the calculation for ideal transformers.

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vroomba03
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Homework Statement


We have a transformer, the primary coil has 120V and secondary coil has 6V, if you put 8V in secondary coil, what will be the voltage in the primary coil.


Homework Equations


v1/v2 = n1/n2 where v is voltage and n is turns


The Attempt at a Solution


So i was thinking that the number of coils is going to be constant because there is no mention of them changing. So in that case the 120v/6v has to equal x/8v, which you would just solve for x, which comes out to 160v. That seemed kind of simple, so I wasnt sure i was doing that right. Any thoughts?
 
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vroomba03 said:

Homework Statement


We have a transformer, the primary coil has 120V and secondary coil has 6V, if you put 8V in secondary coil, what will be the voltage in the primary coil.


Homework Equations


v1/v2 = n1/n2 where v is voltage and n is turns


The Attempt at a Solution


So i was thinking that the number of coils is going to be constant because there is no mention of them changing. So in that case the 120v/6v has to equal x/8v, which you would just solve for x, which comes out to 160v. That seemed kind of simple, so I wasnt sure i was doing that right. Any thoughts?

Yup, it's as simple as that for ideal transformers.
 
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