What happens when deforming a coil on a magnetic field

  • Thread starter An1MuS
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  • #1
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1) Having in mind the Faraday-Lenz law, i'm still not sure if anything happens to it? [1) SOLVED]

The area is always the same, the flux idem, flux density as well, so at first glance it would appear nothing happens?

OOfKo.jpg


This problem was on a exam.

2) Let's say i have a permanent magnet and a wire like in the picture, should there be an emf, in the wires if we move them into or out of the magnetic field of the magnet? Being a wire, it can only produce flux lines (2-D) and they can't oppose the change in magnetic field. The one on the right because it only produces flux perpendicular to the magnetic field of the magnet, the one on the right, because it's a circle, and if one side of the circle counteracts the change of magnetic flux the other helps it.

So basically i think this can be resumed in: can a straight line of wire have an emf on its ends generated by the change of the flux its subject to?

Cegih.png


Please do correct any errors in my thinking.
 
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Answers and Replies

  • #2
tiny-tim
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Hi An1MuS! :smile:
The area is always the same …
The area isn't the same :redface:

if you deform a circle (keeping the perimeter the same), the area must decrease. :wink:
 
  • #3
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Hi An1MuS! :smile:


The area isn't the same :redface:

if you deform a circle (keeping the perimeter the same), the area must decrease. :wink:
Ups, i was thinking of perimeter, good thing you mentioned it -__- 1) solved then. Thanks.

What about 2) ?
 
  • #4
tiny-tim
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a straight wire moving through a magnetic field will receive an emf

a square wire moving through a uniform magnetic field will receive opposite emfs in opposite sides, so the total emf will be zero

this is because opposite sides are moving in the same direction

if you deform the square so that opposite sides move in opposite directions, the emfs will add :wink:

(and the total emf will of course be proportional to the change in area)
 
  • #5
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But if the question include the posibility of stretching the wires so when you pull the coil to the elliptical shape AND still maintain the same area inside the coil. AND IF the B field is uniform, the induced EMF should be the same, isn't it?

Sure the exam question don't mean this?
 
  • #6
tiny-tim
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But if the question include the posibility of stretching the wires so when you pull the coil to the elliptical shape AND still maintain the same area inside the coil.
you can do that for a rectangle, but not for a circle

for a fixed perimeter, the circle has a strictly greater area than any other shape

(the ancient greeks knew that!)
 
  • #7
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tiny-tim you said a straight wire would have an emf induced

fFJop.png


did you mean like this?

(Sorry for my paint skills)
 
  • #9
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you can do that for a rectangle, but not for a circle

for a fixed perimeter, the circle has a strictly greater area than any other shape

(the ancient greeks knew that!)
I meant IF the wire is stretchable ( big if) and you manage to pull stretch the wires it so that the area inside the ellipse is still equal to the circle it is stretched from. I am worry it is a trick question!!!

No, if wire is not stretchable, when you pull it like in the diagram, the area decrease and all bets are off.
 

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