Similarly to the general rule in physics discussed in Sec. 4.3, the perceptibles in BM do not depend on details of particle trajectories. This is seen from Eqs. (15) and (16), Which say that probability of a perceptible is obtained by integrating out over all microscopic positions $$p^{\mathrm {(appar)}}_l=\int_{\text {supp }\rm {A_1}}d\vec x \int d\vec y |\Psi(\vec x,\vec y)|^2.$$ Intuitively, it says that the precise particle positions are not very much important to make measurable predictions. It is important that particles have some positions (for otherwise it is not clear how can a perceptible exist), but it is much less important what exactly those positions are. That is why BM (with trajectories) makes the same measurable predictions as standard QM (without trajectories).
It is extremely important not to overlook the general idea above that the precise particle positions are not essential. For otherwise, one can easily make a false "measurable prediction” out of BM that seems to differ from standard QM, when in reality there is no such measurable prediction. The general recipe for making such a false "measurable prediction” out of BM is to put too much emphasis on trajectories and ignore the perceptibles. A lot of wrong “disproofs of BM” of that kind are published in the literature.
By a peer pressure of making new measurable predictions out of BM, even distinguished Bohmians sometimes fall into this trap. For instance, some try to make new measurable predictions of arrival times by computing the arrival times of microscopic BM trajectories (see e.g. [32, 33]). However, the microscopic trajectories are not perceptibles, so the arrival times obtained from microscopic BM trajectories may be rather deceptive from a measurable point of view. To make a measurable prediction, one must first specify how exactly the arrival time is measured [34] which requires a formulation of the problem in terms of a perceptible. When the problem is formulated in that way, BM makes the same measurable predictions as standard QM, despite the fact that there is no time operator in standard QM (recall also the discussion around Eq. (21)
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Why cannot BM trajectories be observed? Or more precisely, why cannot a single measurement reveal a Bohmian particle position with a precision better than the spatial width of the wave function? This is not only because Bohmian positions are not perceptibles; after all atom positions are also not perceptibles, yet electron microscope can be used to observe atom positions. The true reason why Bohmian positions cannot be observed with a precision better than the spatial width of the wave function is because there are no local interactions (in the sense explained in Sec. 4.2) between BM particles. To make an analogy, trying to observe a Bohmian trajectory is like trying to observe the Moon’s trajectory by watching tides. Classical gravity is a long range force, so the observation of effect on B caused by A does not directly reveal the position of A. That is why we cannot observe the Moon’s trajectory by watching tides. That is also why there is no direct evidence for the existence of astrophysical dark matter (hypothetic matter with negligible interactions, except gravitational). In that sense, the absence of direct evidence for BM trajectories can be thought of as being analogous [14] to the absence of direct evidence for dark matter.