What is 2nd Sine? Solving a Triangle with 13.5 Hypotenuse

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Homework Help Overview

The discussion revolves around solving a triangle with a hypotenuse of 13.5 and a height of 11.8, specifically focusing on finding the measure of angle P. The original poster mentions needing to use a function referred to as "2nd sine" to determine the angle.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of the sine function and its inverse to find angle P. There are attempts to clarify the meaning of "2nd sine," with suggestions that it refers to the inverse sine function. Questions arise regarding the placement of angle P and the accuracy of the given values.

Discussion Status

Participants are exploring different interpretations of the problem and the functions involved. Some have provided guidance on using inverse functions on calculators, while others are questioning the accuracy of the textbook's information and the values provided.

Contextual Notes

There are indications that there may be a typo in the textbook regarding the values or instructions, as some participants express confusion over the calculations leading to different angle measures.

Liam C
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Homework Statement


A triangle with a hypotenuse of 13.5 and height of 11.8. Find the measure of angle P.
Angle p is on the same line as the 90 degree angle and I found out that it must be sine.

Homework Equations


sine = opposite/hypotenuse

The Attempt at a Solution


sin p = 11.8/13.5
sin p = .874

Textbooks answer: sin p = 71.468
It says I need to use something called 2nd sine like this: 2nd sin(11.8/13.5), which I can't find on my calculator and hasn't been introduced in the textbook until now. It doesn't explain 2nd sin. What does it mean and how do I go about solving this on my own?
 

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It would appear "2nd" is supposed to be an inverse function: You're finding the angle whose sine is 11.8/13.5. That is often written as ## \sin^{-1}(11.8/13.5) ##. The "2nd" is apparently referring to a "second" (inverse) function.
 
Liam C said:
Textbooks answer: sin p = 71.468
That looks more like the angle p. Try looking for arcsin on your calculator to go from the sine value to the angle...

EDIT -- Beaten to the punch by Charles :smile:
 
Liam C said:
Textbooks answer: sin p = 71.468
BTW, I get a slightly different answer for the angle. I'll check the rest of your work (unless Charles beats me to that too!).
 
Liam C said:
Angle p is on the same line as the 90 degree angle and I found out that it must be sine.
Are you sure you have the angle p shown in the right place?
 
berkeman said:
Are you sure you have the angle p shown in the right place?
Yes.
 
berkeman said:
Are you sure you have the angle p shown in the right place?
Also I tried using the inverse sine and it didn't give me the correct answer. It gives me 60.9
 
Liam C said:
Yes.
So what do you get for arcsin(11.8/13.5 )

EDIT -- Right, that's what I got.
 
berkeman said:
So what do you get for arcsin(11.8/13.5 )

EDIT -- Right, that's what I got.
I don't know how to do that, unfortunately.
 
  • #10
Liam C said:
I don't know how to do that, unfortunately.
arcsine is the same as inverse sine.
 
  • #13
Liam C said:
hypotenuse of 13.5 and height of 11.8.
Maybe double-check those numbers -- maybe there is a typo digit in there somewhere that is giving us the wrong answer...
 
  • #14
berkeman said:
Maybe double-check those numbers -- maybe there is a typo digit in there somewhere that is giving us the wrong answer...
Unfortunately no :(
I am starting to think there might be a typo in the textbook given the fact what it's telling me to do gives me a completely wrong answer
 
  • #15
Liam C said:

The Attempt at a Solution


sin p = 11.8/13.5
sin p = .874

Textbooks answer: sin p = 71.468
arcsin(12.8/13.5) = 71.468. That looks to be the typo.:smile:
 
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  • #16
berkeman said:
arcsin(12.8/13.5) = 71.468. That looks to be the typo.:smile:
Ah, thanks so much! A silly textbook typo had me so confused! :smile:
 
  • #17
Liam C said:
It says I need to use something called 2nd sine like this: 2nd sin(11.8/13.5),
Some calculators have a button labeled "2nd". When you press it, the calculator uses the function behind (or above) a given button.

On my calculator, a CASIO model, there is a button labeled SHIFT, in orange letters. Just above my button labeled "sin" is label, in orange letters, for the inverse function "sin-1". There are inverse functions for sine, cosine, and tangent, as well as log, ln (natural log) and a few others. All of the inverse functions are accessed by pressing the SHIFT button. On yours I'd be willing to bet there's a "2nd" button.
 
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  • #18
Mark44 said:
Some calculators have a button labeled "2nd". When you press it, the calculator uses the function behind (or above) a given button.

On my calculator, a CASIO model, there is a button labeled SHIFT, in orange letters. Just above my button labeled "sin" is label, in orange letters, for the inverse function "sin-1". There are inverse functions for sine, cosine, and tangent, as well as log, ln (natural log) and a few others. All of the inverse functions are accessed by pressing the SHIFT button. On yours I'd be willing to bet there's a "2nd" button.
Yes, shift did it :)
 

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