What is a Non-zero Vector in R^3 that Belongs to Two Given Spans?

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SUMMARY

The discussion focuses on finding a non-zero vector in R^3 that belongs to both the span of vectors y = (1, 0, 0) and u = (0, 0, 1), as well as the span of vectors v = (1, 1, 1) and w = (2, 3, -1). The solution involves using the scalar triple product to determine the intersection of the two spans, leading to the conclusion that the vector 'a' must satisfy the equations derived from the determinants of the respective spans. The final solution indicates that the vector 'a' can be expressed with specific values for its components, confirming its validity.

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  • Understanding of vector spans and linear combinations
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  • Familiarity with determinants and their properties in R^3
  • Basic linear algebra concepts, including vector spaces and intersection of planes
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  • Explore the application of determinants in solving systems of linear equations
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Students and educators in linear algebra, mathematicians working with vector spaces, and anyone interested in understanding the geometric properties of vectors in R^3.

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Homework Statement



I require some help to find a non-zero vector in R^3 that belongs both to span {y; u} and to span {v;w} where y = (1; 0; 0); u = (0; 0; 1), v = (1; 1; 1) and w = (2; 3;-1),
I need to know if my below solutions is ok.Thank you

2. The attempt at a solution
Let 'a' be the required vector.
I need to satisfy [a,y,u]=0 and [a,v,w]=0; where [a,y,u] is the scalar triple product of a, y and u.
Since span of two given vectors is a plane, 'a' lies on the intersection of two planes hence 'a' is the vector along the line of intersection of the two planes.
=>...[A,B,C]=det(ABC)...so det(a,y,u)=>y=0...and det(a,v,w)=-4x+y+z=0...y=0,so x=1 and z=4
 
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Right!
 
ok:)...thanks
 

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