# What is an asymptote and why doesn't parabola have one?

1. Oct 1, 2007

### Skhandelwal

The thing I have noticed is that parabola's angle from the x axis keeps increasing...meaning the object is decreasing from that direction...if that is the case, then how does it go on in that direction forever even though, its speed going in that direction keeps decreasing?

At what rate something is decreasing if it has a parabola?(Plz don't explain it in formula, I know that explanation too...I just want more conceptual explanation) I know when x is in the denominator, that when there are 2 asymptotes.

2. Oct 1, 2007

### Eighty

A function f(x) has an asymptote if it "looks like" a straight line when x tends to $\pm\infty$. More precisely, if the distance $|f(x)-\text{the line}|$ tends to 0.

A parabola doesn't have one. Suppose there was one (draw an arbitrary line in the same graph). Then, at some point, the parabola will rush past that line and keep going away from it, so it wasn't an asymptote.

3. Oct 2, 2007

### Skhandelwal

Thx for that approach but I guess I wasn't really looking for a counter-example...more like the real WHY? Which is based w/o math...like a drawing...if someone drew an infinite parabola, how can it approach infinity toward the x-axis...b/c the rate at which it is approaching x-axis is decreasing.

Btw, this brings the question, at what rate is something deaccelerating if a graph has an asymptote? For instance: y=1/x

4. Oct 3, 2007

### HallsofIvy

The words "accelerating" and "decelerating" have nothing to do with parabolas. If you can phrase the question purely in terms of mathematics rather than physics we might be able to understand it better.

The answer to your first question is really in what you said: "parabola's angle from the x axis keeps increasing". Since it does not approach any one angle, it cannot have an asymptote. The graph of y= x2 "can approach infinity toward the x-axis" because x2 is defined for all x, not matter how large!

5. Oct 3, 2007

### Skhandelwal

But it IS approaching an angle! 180 degrees from the x-axis.

6. Oct 3, 2007

### neg_ion13

I wouldn't look at it in terms of increasing angles. I think that will lead to trying to visually evaluate your question. Think of more like, for each value of X, Y gets much bigger than X. An asymptote is a place where a function is undefined. X^2 is never undefined so it can not have an asymptote. In a nut shell there is not a value of X that can't be squared, so if X can always be squared then any value of X can be used, therefore X can approach infinity.

7. Oct 4, 2007

### Skhandelwal

Well yeah, but as I mention before...I was looking for NONMATHEMATICAL example. It is similar to like this...the doctor tells me, I am dead...but I say...I clearly don't feel dead...he says...well...the machines indicate you are dead so you are dead.

I mean I see that MATH indicate it will go to infinity. But when I look it from my eyes, that is just not what I see. And I just wish there was a more satisfying way to understand this.

8. Oct 4, 2007

### neg_ion13

You can't define something approaching infinity by "looking at it". What you think is common sense may not be quite how it works. Also, I did not give you a mathematical example. There were no calulations in what I posted. It goes to infinity is the answer your looking for. If it doesn't stop how can it approach an asymptote?

9. Oct 6, 2007

### codec9

I see the problem. It is right to say that the angle of the section you are looking at will keep increasing with respect to the x-axis. If I understand this correctly, the angle will approach 90 degrees. 180 degrees would mean it is parallel to the x-axis if you are measuring with respect to it.

You can look at it from the angles all you want and that is perfectly correct. However, while every function that does have an asymptote does approach an angle just like the parabola, that is not sufficient grounds to conclude that IF a function approaches an angle THEN it is asymptotic. It's true that asymptotic functions do that. But it is not true that all functions that do that are asymptotic. Tricky, tricky.

The way I like to break it down is this. There is a group of functions that approach a given angle. Some of them are asymptotic, but not all of them. Why? Because an asymptote means the functions can never quite get to some value or other that it gets real close to, and as a result has this angle business. But for a parabola, the function can take in any x value and output any y value. (Not every x is paired with every y.) Actually, it only outputs every y value equal or greater than the bottom of the parabola, of equal to or less than the top if it is pointing down.

The point is: the function must lack the ability to reach a certain VALUE and approach that value arbitrarily closely. I think the difficulty is that, although the parabola gets steeper and steeper, it still keeps going. You just have to back up and "look at" more.

What might break your spell is this. The parabola can take in ANY x value as its input. The height is the x value squared. Where is the y value? Well, it is straight above the x! So if we can do this for any x value, then we might as well be plotting y = x because that does the same thing. It takes in a "width" and outputs a "height" directly above it. Alas, the x in y = x is not squared so the heights are not as high, but that does not matter. That has to do with the shape not the relationship I am talking about here (how y's get mapped from the x).

If there is a shift left or right, it goes over that many units so its no problem. Just shift your axes and you are back to the original. Same for up or down.

To repeat, anywhere on the x axis you choose, there is a y some distance above the x. The thing is not limited by width and certainly not by height, although it can't go above/below the vertex or whatever it's called.

Last edited: Oct 6, 2007
10. Oct 9, 2007

### Skhandelwal

OMG, someone finally understood my question! lol, but still doesn't solve the problem...the thing is...I like to look at it as if it is similar to that paradox....here it is

Paradox: Lets say you want to travel 1 meter, what you do is that you travel half the distance: .5 meter, then travel half the distance of what you have already traveled:.5 and keep repeating the process infinitely so you keep getting closer, but never get there.

Based on this paradox...I believe that if it is keep approaching 90 degrees angle....even though it is getting closer to infinity, it can never achieve it conceptually..get it?

11. Oct 9, 2007

### codec9

infinity has to do with height, not angle. y = x goes to infinity in either direction, but it is a clear 45 degrees with respect to the x-axis no matter where you are.

12. Oct 9, 2007

### CRGreathouse

That's Zeno's paradox of the arrow, yes? The resolution is that you *can* travel an infinite number of steps infinite time, provided the total distance is finite (and sufficiently small).

Because the parabola has an increasing slope (= angle from the x-axis) it cannot have an asymptote other than a vertical asymptote. If the parabola had a vertical asymptote then there would be some point where you could get infinitely large values as you became arbitrarily close to that point, but there is no such point on the parabola. Take y=x^2 as an example; for every x the limit as x approaches k of y is just k^2, which is finite; it's not unbounded in any finite interval.

13. Oct 11, 2007

### Skhandelwal

See thats the point...all the explanations that people have been giving me have to do w/ mathematical calculations...why can't someone just teach me the concept WHY it does approach infinity?

14. Oct 11, 2007

### MaWM

Ok. no sweat. Its because x^2 is defined for all x. x^2 gets bigger and bigger, faster and faster, but there is no x where it gets infinitely large. It keeps getting steeper and steeper. Its slope approaches verticality. But thats not enough to have an asymptote. You have to approach vertically *fast enough*. x^2 does not. it takes infinitely many x s before x^2 becomes vertical.

If you forgive the mathematical example, consider the series SIGMA(1/n) . Each step is smaller than the last. The size of the terms goes to zero, and yet their sum is unbounded. What does this have to do with the parabola? Well, if you look at the distance it takes for the slope of the parabola to double, that distance gets smaller and smaller as the x gets larger. But it still takes infinitely large x until the slope goes to infinity.

Other functions, like 1/x, do have asymptotes because their slope increases much more quickly than x^2

15. Oct 11, 2007

### stewartcs

An asymptote is a straight line associated with a curve such that as a point moves along an infinite branch of the curve the distance from the point to the line approaches zero and the slope of the curve at the point approaches the slope of the line.

The word's origin is Greek and means "not intersecting". It's used in mathematics to merely describe an imaginary line that a curve cannot cross.

Is that conceptual enough?

16. Oct 11, 2007

### Skhandelwal

LOL....did you even read my question? I am not asking what an asymptote is...I am asking...why doesn't parabola has a verticle one.

btw,(this is a mathematical question :-) at what rate is something decreasing if it has an asymptote?

17. Oct 11, 2007

### stewartcs

What is an asymptote and why doesn't parabola have one?

Is this not the title of this thread??

18. Oct 11, 2007

### stewartcs

So first you don't like the mathematical answers, but then you admit its a mathematical question??

19. Oct 11, 2007

### stewartcs

A parabola is a continuous function. That means it doesn't have any discontinuities. An asymptote creates a discontinuity in the would be path of a parabola.

An asymptote is a straight line; its rate of change is zero.

20. Oct 11, 2007

### Hurkyl

Staff Emeritus
Consider the graph of y = 10 / (x^2 + 1).

Is the line y=0 an asymptote?
Is the line y=1 an asymptote?
Is the line y=-1 an asymptote?

(The answers are not all the same)

Incidentally, projectively, asymptotes are simply tangent lines: they are tangent at infinity. A parabola has only one point at infinity, and the tangent line there is the line at infinity.

21. Oct 11, 2007

### Skhandelwal

Ok...there seems to be a huge misunderstanding....first of all, stewartcs, I apologize for how I reacted to your answer...I got so involved in the parabola...I forgot about that...about the asymptote...notice...I am talking about a PARABOLA....so my question is...at what rate is the PARABOLA decreasing when it has an asymptote...notice here, I am not asking the rate at which the asymptote is changing...but the parabola's rate which is being affected by the asymptote...now...this question was suppose to be mathematical b/c giving a conceptual answer to this seems a bit difficult and unneccesary. So for the rate...I want some number...but for the question:Why doesn't parabola have an asymptote....I need a conceptual answer....Is it clearer now?

I sure do hope so.

22. Oct 11, 2007

### stewartcs

Parabolas do not have asymptotes, therefore your question is nonsensical. It's like saying why is a circle square?

If you are instead asking what is the rate of change at any local vertex of a parabola, then the answer is zero.

23. Oct 11, 2007

### Skhandelwal

My bad again...lemme rephrase the question....at what rate does a FUNCTION decrease when it has an asymptote?(mathematical answer)

Why doesn't parabola have an asymptote?(conceptual answer-don't give me a counter argument...meaning...don't tell me if it would...it would be this kinda function...stuff like that...but tell me the actual WHY.)

24. Oct 11, 2007

### codec9

stewart, regarding post 19 the rate of change of a line is not automatically 0. I don't know where you got that from. A vertical line has an infinite rate of change; y = x has a rate of change of 1.

Skhandelwal, was there something wrong with my explanations on posts 9 and 11?
MaWM's first paragraph in post 14 is the concept you are looking for I think. So a function is just a rule basically. It might be easier to describe by talking about sets of stuff. You start with a set of numbers and do something to them and end up with another set of numbers. This is not really mathematical. In the case of the parabola, you start with all the numbers from -infinity to +infinity and, for each, you times it by itself and you end up with that corresponding set.

If you agree that what goes into the function goes to infinity in either direction, and all we do to each of those things is square it and therefore make it bigger in absolute value (except for fractions), how do you not see that the bigger thing is not going to infinity as well? The bigger thing gets to infinity faster!

Now for it not to have an asymptote the outputs can't just go to infinity, because that can happen with a vertical asymptote like in 1/x, but the real trick is that the output is right above the input, and the inputs are from -infinity to +infinity, combined with the outputs not being limited as well. So there is not any sort of asymptote or "line where the function arbitrarily closely approaches without getting there."

A function can decrease or increase at any rate and have an asymptote. The asymptote does not have to be vertical, it could be y = 3x, in which case the function would be increasing at the rate of 3.

25. Oct 11, 2007

### MaWM

ok.. first off. there are polynominals. X^2 increases quickly, but not quickly enough. x^100 increases far more quickly, but still not quickly enough (to have an asymptote). Beyond any polnominal, there are functions of the form 2^x. These increase more quickly than *any* polynomial, no matter how high the power. But they *still* dont increase quickly enough to have an asymptote. The simplest example of a function that does have an asymptote is 1/x . this function increases even more quickly than any function of the form n^x or n^n^x or n^n^n^x etc. Every function that increases more quickly than 1/x does have at least one asymptote. 1/x^2, 1/x^100 etc