What is going on here? (Heat equation w/ Neumann conditions)

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SUMMARY

The discussion centers on solving the heat equation \( u_t = u_{xx} \) on the interval \( 0 < x < 1 \) with no-flux boundary conditions and the initial condition \( u(x,0) = \cos(\pi x) \). The solution is expressed as \( u(x,t) = B_0 + \sum B_n \cos(n\pi x) e^{-n^2 \pi^2 t} \) with \( L = 1 \) and \( \sigma = 1 \). The user encounters an issue calculating \( B_n \), resulting in \( B_n = 0 \) after applying the cosine product identity, prompting a request for clarification on the error in their approach.

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Homework Statement



Solve the heat equation

ut=uxx

on the interval 0 < x < 1 with no-flux boundary conditions. Use the initial condition

u(x,0)=cos ∏x​

Homework Equations



We eventually get u(x,t)= B0 + ƩBncos(n∏x/L)exp(-n22σ2t/L2)

where

L=1 and σ=1 in our case.

B0 is given by (1/L)∫[0,L]u(x,0)dx

and Bn by (2/L)∫[0,L]u(x,0)cos(n∏x/L)dx

The Attempt at a Solution




Well, I keep getting Bn = (2/L)∫[0,L]u(x,0)cos(n∏x)dx = 0 after using the trig identity cos(u)cos(v)=(1/2)(cos(u+v)+cos(u-v)).

What's happening here? I've checked my steps many times.
 
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