Wave equation, taut string hit with hammer

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Homework Help Overview

The discussion revolves around a wave equation problem involving a string of length L that is fixed at both ends. The string is struck in the middle with a hammer of width a, leading to specific initial conditions for the wave function and its time derivative.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the initial conditions for the Fourier series representation of the wave equation, with some questioning the limits of integration and the effect of the hammer's size on the wave behavior.

Discussion Status

Some participants have provided clarifications regarding the equations and the parameters involved, such as the relationship between c and v. There is ongoing exploration of the implications of the hammer's width on the wave's initial conditions, with no explicit consensus reached yet.

Contextual Notes

Participants note potential discrepancies in variable notation (e.g., using l instead of L) and the need for careful consideration of the intervals where the initial conditions apply. The discussion also highlights the importance of correctly applying Fourier series principles in this context.

Taylor_1989
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Homework Statement


A string of length L is fixed at both ends ##u(0,L)=u(L,t)=0## The string is struck in the middle with a hammer of width a, leading to an intial condtion ##u(x,0)=0## and

$$U_t(x,0)=v_0 $$ for $$\frac{l}{2}-\frac{a}{2} \leq x \leq \frac{l}{2}+\frac{a}{2} $$

and

$$U_t(x,0)=0 $$ other wise

I have printed screen in the question Just encase it make no sense what I have wirtten

upload_2017-12-10_16-21-12.png


I am not going to put full working, I am having trouble with one particular part the intial condtions for my Fourier series.

Homework Equations


$$U_t(x,0)=\sum_{n=1}^\infty \left(-\frac{n\pi c}{L}\right)B_n sin(\frac{n\pi}{L}x)$$ [1]

$$\left(-\frac{n\pi c}{L}\right)B_n=\frac{2}{l}\int _0^lv_0sin\left(\frac{n\pi }{L}x\right)dx\:$$ [2]

$$B_n=-\frac{2v_0}{-n\pi c}\int _{\left(\frac{L}{2}-\frac{a}{2}\right)}^{\frac{L}{2}+\frac{a}{2}}sin\left(\frac{n\pi }{L}x\right)dx\:$$ [3]

The Attempt at a Solution



[3] soultuion
$$B_n=\frac{2Lv_0}{n^2\pi ^2c}\left(cos\left(\frac{n\pi }{2}\left(\frac{L+a}{L}\right)-cos\left(\frac{n\pi }{2}\left(\frac{L-a}{L}\right)\right)\right)\right)$$

I believe I have gone wrong with the limits and my problem lies in how the size of the hammer is effecting the wave in this case, could someone please advise, thanks in advace
 

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Taylor_1989 said:

Homework Statement


A string of length L is fixed at both ends ##u(0,L)=u(L,t)=0## The string is struck in the middle with a hammer of width a, leading to an intial condtion ##u(x,0)=0## and

$$U_t(x,0)=v_0 $$ for $$\frac{l}{2}-\frac{a}{2} \leq x \leq \frac{l}{2}+\frac{a}{2} $$

and

$$U_t(x,0)=0 $$ other wise

I have printed screen in the question Just encase it make no sense what I have wirtten

View attachment 216437

I am not going to put full working, I am having trouble with one particular part the intial condtions for my Fourier series.

Homework Equations


$$U_t(x,0)=\sum_{n=1}^\infty \left(-\frac{n\pi c}{L}\right)B_n sin(\frac{n\pi}{L}x)$$ [1]

$$\left(-\frac{n\pi c}{L}\right)B_n=\frac{2}{l}\int _0^lv_0sin\left(\frac{n\pi }{L}x\right)dx\:$$ [2]

$$B_n=-\frac{2v_0}{-n\pi c}\int _{\left(\frac{L}{2}-\frac{a}{2}\right)}^{\frac{L}{2}+\frac{a}{2}}sin\left(\frac{n\pi }{L}x\right)dx\:$$ [3]

The Attempt at a Solution



[3] soultuion
$$B_n=\frac{2Lv_0}{n^2\pi ^2c}\left(cos\left(\frac{n\pi }{2}\left(\frac{L+a}{L}\right)-cos\left(\frac{n\pi }{2}\left(\frac{L-a}{L}\right)\right)\right)\right)$$

I believe I have gone wrong with the limits and my problem lies in how the size of the hammer is effecting the wave in this case, could someone please advise, thanks in advace

The wave equation has a speed parameter "##v##" in it; why does your solution have no ##v## anywhere? Is your ##c## perhaps equal to the ##v## in the question?
 
Sorry yes my c=v my appolgise. I have also just had a through could I use the indenties for cos(a+b) and cos(a-b) to solve this problem
 
Last edited:
Taylor_1989 said:
I am not going to put full working, I am having trouble with one particular part the intial condtions for my Fourier series.

Homework Equations


$$U_t(x,0)=\sum_{n=1}^\infty \left(-\frac{n\pi c}{L}\right)B_n sin(\frac{n\pi}{L}x)$$ [1]

I agree up to here except I don't have a minus sign. But that shouldn't affect the final answer.

$$\left(-\frac{n\pi c}{L}\right)B_n=\frac{2}{l}\int _0^l v_0 \sin\left(\frac{n\pi }{L}x\right)dx$$
That isn't quite right. Apparently the ##l## should be ##L##, but the function isn't ##v_0## on that interval. So it is better written$$
\left(-\frac{n\pi c}{L}\right)B_n=\frac{2}{L}\int _0^L u_t(x,0) \sin\left(\frac{n\pi }{L}x\right)dx$$ $$
\left(-\frac{n\pi c}{L}\right)B_n=\frac{2}{L}\int _{\frac L 2 - \frac a 2}
^{\frac L 2 + \frac a 2 }v_0 \sin\left(\frac{n\pi }{L}x\right)dx$$

$$B_n=-\frac{2v_0}{-n\pi c}\int _{\left(\frac{L}{2}-\frac{a}{2}\right)}^{\frac{L}{2}+\frac{a}{2}}sin\left(\frac{n\pi }{L}x\right)dx\:$$ [3]

The Attempt at a Solution



[3] soultuion
$$B_n=\frac{2Lv_0}{n^2\pi ^2c}\left(cos\left(\frac{n\pi }{2}\left(\frac{L+a}{L}\right)-cos\left(\frac{n\pi }{2}\left(\frac{L-a}{L}\right)\right)\right)\right)$$

I believe I have gone wrong with the limits and my problem lies in how the size of the hammer is effecting the wave in this case, could someone please advise, thanks in advace

I didn't check your final answer but I don't see any obvious major errors.
 

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