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freshyy
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This is a general question that i am confused about. If I throw a ball up, then is the distance that it reaches at the very top the y or y-initial? Also, is this y or y-initial positive or negative?
freshyy said:This is a general question that i am confused about. If I throw a ball up, then is the distance that it reaches at the very top the y or y-initial? Also, is this y or y-initial positive or negative?
berkeman said:You can define your coordinates however is the most convenient for solving any particular problem. The simplest 2-d coordinate system for projectile motion problems would be to put the origin on the ground, with the x-axis horizontal and the y-axis vertical. That means y=0 is at ground level, so if you are 6 feet tall and throw a ball up, then y(t=0)=6', and Vy(0)= whatever velocity you release the ball at time t=0. The height at the top of the ball's travel will depend on Vy(0) at the release point y(0)=6' plus however long it takes for the ball to stop moving up. Use an equation like this...
y(t) = y(0) + Vy(0)*t + 1/2*ay*t^2
Where a = the acceleration due to gravity, which in this case is -9.8m/s^2.
Does that help?
berkeman said:You can define your coordinates however is the most convenient for solving any particular problem. The simplest 2-d coordinate system for projectile motion problems would be to put the origin on the ground, with the x-axis horizontal and the y-axis vertical. That means y=0 is at ground level, so if you are 6 feet tall and throw a ball up, then y(t=0)=6', and Vy(0)= whatever velocity you release the ball at time t=0. The height at the top of the ball's travel will depend on Vy(0) at the release point y(0)=6' plus however long it takes for the ball to stop moving up. Use an equation like this...
y(t) = y(0) + Vy(0)*t + 1/2*ay*t^2
Where a = the acceleration due to gravity, which in this case is -9.8m/s^2.
Does that help?
freshyy said:Also, the time that the ball takes to come down is twice the time the ball takes to reach its maximum height, right?
Yea, in understand it now thank you.berkeman said:Well, I mean the two times from release to apex, and from apex to hitting the ground. Those are not equal.
The sign of y when a ball is thrown up depends on the direction of the ball's motion. If the ball is moving upwards, the sign of y is positive. If the ball is moving downwards, the sign of y is negative.
Yes, the sign of y can change if the ball is thrown at an angle. If the ball is thrown upwards at an angle, the sign of y will still be positive. However, if the ball is thrown downwards at an angle, the sign of y will be negative.
The sign of y does not affect the ball's trajectory directly. It is simply a way to indicate the direction of the ball's motion along the y-axis. The ball's trajectory is primarily influenced by factors such as initial velocity, angle of throw, and gravity.
Yes, the sign of y can change during the ball's flight. For example, if the ball reaches its highest point and begins to fall back down, the sign of y will change from positive to negative.
Yes, the sign of y is important in determining the ball's position along the y-axis. It helps us understand the direction of the ball's motion and can be used in equations to calculate its position at a specific time.